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bearhunter [10]
2 years ago
5

Pls helpppppppp!!!!!!!

Chemistry
1 answer:
aniked [119]2 years ago
8 0

Answer:

a:  k2 02

Explanation:

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Katherine was given a tiny lamb by her uncle. The lamb was a runt and had to be fed by hand. Every 3 hours
lorasvet [3.4K]

Answer:

2.32 liters

Explanation:

you would just divide 24 by 3 which is 8 and multiply 290 by it which is 2320 and divide by 1000 which is 2.32

4 0
3 years ago
Please help me.
kirza4 [7]

Taking into account the definition of density, the density of the sample is 0.5 \frac{g}{mL}.

It is necessary yo know that density is defined as the property that matter, whether solid, liquid or gas, has to compress into a given space.

In other words, density allows you to measure the amount of mass in a certain volume of a substance.

Then, the expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:

density=\frac{mass}{volume}

In this case, you know:

  • mass= 6 g
  • volume= 12 mL

Then, replacing in the definition of density:

density=\frac{6 g}{12 mL}

Solving:

<u><em>density= 0.5 </em></u>\frac{g}{mL}<u><em /></u>

Finally, the density of the sample is 0.5 \frac{g}{mL}.

Learn more about density:

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  • <u>brainly.com/question/1462554?referrer=searchResults</u>
7 0
3 years ago
Calculate the specific heat capacity for a 15.3-g sample of gold that absorbs 87.2 J when its temperature increases from 35.0 °C
diamong [38]

Answer:

The specific heat of gold is 0.129 J/g°C

Explanation:

Step 1: Data given

Mass of gold  = 15.3 grams

Heat absorbed = 87.2 J

Initial temperature = 35.0 °C

Final temperature = 79.2 °C

Step 2:

Q = m*c*ΔT

⇒ Q =the heat absorbed = 87.2 J

⇒ m = the mass of gold = 15.3 grams

⇒ c = the specific heat of gold = TO BE DETERMINED

⇒ ΔT = The change in temperature = T2 - T1 = 79.2 - 35.0 = 44.2 °C

87.2 J = 15.3g * c * 44.2°C

c = 87.2 / (15.3 * 44.2)

c = 0.129 J/g°C

The specific heat of gold is 0.129 J/g°C

4 0
3 years ago
Number 14? Please :)
ASHA 777 [7]
Evaporated is the answer
4 0
2 years ago
What is the concentration of NaCI in an aqueous solution that contains 0.032 grams of NaCI in 600. Grams of the solution
jolli1 [7]

Answer:

0.00032 Grams of NaCl per 1 gram of the solution

Explanation:

8 0
3 years ago
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