Answer:
The ball will have a displacement of 0.5*15.0=7.5m after 0.5 seconds. The velocity of the ball will be 15.0 m/s, since it is not acted on by any forces except gravity (which acts in the direction opposite of the velocity).
Explanation:
We know this is the answer because, according to the kinematic equation:
v^2=u^2+2*a*d
0=15.0^2+2*(-9.8)*d
d=-7.5m
Answer:
E. Some charges in the region are positive, and some are negative.
Explanation:
Electric potential is given as;

where;
W is the work done in moving a charge between two points which have a difference in potential
Q is quantity of charge in the given region
If the electric potential at a given point in the region is zero, then sum of the charges in the given region must be equal to zero. For the charges to sum to zero, some will be positive while some will be negative,.
Therefore, the correct statement in the given options is "E"
E. Some charges in the region are positive, and some are negative.
Explanation:
It depends because the higher the object is, the bigger the shadow, however, the object should be close to the line directly from the sun, for you to see the shadow visible.
The final velocity of the Maserati after accelerating at the rate of 85 m/s² for 5 seconds is 431m/s.
<h3>How to calculate the final velocity a moving object?</h3>
From the first equation of equation of motion, final velocity is the sum of the initial velocity and the product of acceleration and time.
It is expressed as;
v = u + at
Where v is final velocity, u is initial velocity, a is acceleration and t is time elapsed.
Given the data in the question;
- Initial velocity u = 6m/s
- Acceleration a = 85m/s²
- Elapsed time t = 5s
- Final velocity v = ?
Plug the given values into the first equation of motion and solve for v.
v = u + at
v = 6m/s + ( 85m/s² × 5s )
v = 6m/s + 425ms/s²
v = 6m/s + 425m/s
v = 431m/s
The final velocity of the Maserati after accelerating at the rate of 85 m/s² for 5 seconds is 431m/s.
Learn more about the first equation of equation here: brainly.com/question/20381052
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