Answer:
Part a)
Mass of m2 is given as

Part b)
Angular acceleration is given as

Part c)
Tension in the rope is given as

Explanation:
Part a)
When m1 and m2 both connected to the cylinder then the system is at rest
so we can use torque balance here




Part b)
When block m_2 is removed then system becomes unstable
so force equation of mass m1

also we have

now we have




so angular acceleration is given as



Part c)
Tension in the rope is given as



Answer:
The second object takes 2.28 s to fall the 25.5 m.
Explanation:
In this case, both objects take the same time to fall, since <em>no vertical velocity is added </em>to any of them.
You can also confirm this by sepparating the second's object movement into its two directions: in the horizontal one, we have <em>linear uniform motion, </em>and in the vertical one, we have <em>free fall, </em>with exactly the same characteristics as for the first object.
Answer:
Not possible
Explanation:
Unless there's some extra external force to keep both particles at rest after the collision, the momentum must be conserved before and after the collision.
So before the collision, 1 particle is at rest, 1 not -> total momentum is non-zero
After the collision, both particles are at rest -> total momentum is zero which is different from before.
Therefore this is not possible.