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Viefleur [7K]
4 years ago
8

The tenth pair of cranial nerves is the longest in the body and leaves by way of the jugular foramen. These nerves are called th

e____________.
Physics
1 answer:
tekilochka [14]4 years ago
4 0

Answer:

Vagus nerves

Explanation:

The vagus nerves are the tenth pair of cranial nerves

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The work function of cesium is 1.96 eV. If radiation of wavelength 4.00 × 10^2 nm is incident on the surface, find the kinetic e
nata0808 [166]
I have a note here that might help you solve the problem on your own:

According to the law of conservation of energy 

The energy of the photon is used in overcoming the workfunction of the metal, and the excess energy goes as the kinetic energy of the electron. 

<span>Photon Energy = Work function of Cs + KE of electron 
</span>

I hope my guide has come to your help. God bless and have a nice day ahead!
8 0
3 years ago
Describe the motion of a swing that requires 6 seconds to complete one cycle. What is its period and the frequency? Round to the
shutvik [7]

Period = 6 seconds and frequency = 0.167Hz .

<u>Explanation:</u>

We have , the motion of a swing that requires 6 seconds to complete one cycle. Period is the amount of time needed to complete one oscillation . And in question it's given that 6 seconds is needed to complete one cycle. Hence ,Period of the motion of a swing is 6 seconds . Frequency is the number of vibrations produced per second and is calculated with the formula of  \frac{1}{t} . SI unit of frequency is Hertz or Hz. We know that time period is 6 seconds so frequency =   \frac{1}{t}

⇒ frequency = \frac{1}{time}

⇒ frequency = \frac{1}{6}

⇒ frequency = 0.167Hz

Therefore , Period = 6 seconds and frequency = 0.167Hz .

7 0
3 years ago
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8 0
3 years ago
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Which statements are true about the flow of blood in the body? Check all that apply.
Trava [24]

Answer:

i need some explanation

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4 0
4 years ago
Please help!!! I have a physics exam tomorrow and I just can't wrap my head around this one!
Ainat [17]

The total electrostatic force on charge A is 28 \mu N

Explanation:

The magnitude of the electrostatic force between two charges is given by Coulomb's law:

F=k\frac{q_1 q_2}{r^2}

where:

k=8.99\cdot 10^9 Nm^{-2}C^{-2} is the Coulomb's constant

q_1, q_2 are the two charges

r is the separation between the two charges

Here we have three positively charged particles A,B and C, located at the following positions:

x_A = 0\\x_B = 10 m\\x_C = 20 m

The magnitudes of the three charges are:

q_A = q_B = q_C = 0.5 \mu C = 0.5\cdot 10^{-6}C

The force exerted by B on A is to the left (because the force between two positive charges is repulsive), and the force exerted by C on A is also to the left (also repulsive). Therefore, the net force on A is just the sum of the two forces exerted by charges B and C:

F_A = F_{BA} + F_{CA} = k\frac{q_B q_A}{(x_B-x_A)^2}+k\frac{q_C q_A}{(x_C-x_A)^2}=\\=(8.99\cdot 10^9) \frac{(0.5\cdot 10^{-6})^2}{(10)^2}+(8.99\cdot 10^9) \frac{(0.5\cdot 10^{-6})^2}{(20)^2}=2.8\cdot 10^{-5} N = 28 \mu N

Learn more about electric force:

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

3 0
3 years ago
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