Question

What would be the volume of a balloon containing 64g of oxygen gas at STP (standard temperature and pressure)? You should be able to obtain this answer by calculation or by using logical reasoning.

Answer 1

Answer: 44.8 L

Explanation:

To find the volume, we would need to use the ideal gas law.

Ideal Gas Law: PV=nRT

We take the given information and plug it into the equation, but first, we have to manipulate the equation so that we are finding volume.

$V=\frac{nRT}{P}$

P= 1.00 atm (STP)

T= 273.15 K (STP)

R= 0.08206 Latm/Kmol

n= $64g*\frac{1mol}{31.998 g O_{2} }=2 mol$

$V=\frac{(2 mol)(0.08206Latm/Kmol)(273.15 K)}{1.00atm} =44.8 L$