The largest value of w (in N)that they can support as shown in equilibrium.
What is equilibrium?
a State of balance between opposing forces or actions that is either static as in nobody acted on by forces whose resultant is zero or dynamic reaction when the rates of reaction in both differentions are equal.
Sol- the total force in x direction is given as,
€Fx=0
T1 sin 37°=T2 sin 53°
100×3/5 =T/2 ×4/5
T2=75 N
The given total force is-
€Fy=0
T1 cos 37°=T2 cos 53°+W
W=80×4/5 -75×3/5
W=19N
Thus
The largest value of W is 19N.
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Answer:
- <em>The volume of 14.0 g of nitrogen gas at STP is </em><u><em>11.2 liter.</em></u>
Explanation:
STP stands for standard pressure and temperature.
The International Institute of of Pure and Applied Chemistry, IUPAC changed the definition of standard temperature and pressure (STP) in 1982:
- Before the change, STP was defined as a temperature of 273.15 K and an absolute pressure of exactly 1 atm (101.325 kPa).
- After the change, STP is defined as a temperature of 273.15 K and an absolute pressure of exactly 105 Pa (100 kPa, 1 bar).
Using the ideal gas equation of state, PV = nRT you can calculate the volume of one mole (n = 1) of gas. With the former definition, the volume of a mol of gas at STP, rounded to 3 significant figures, was 22.4 liter. This is classical well known result.
With the later definition, the volume of a mol of gas at STP is 22.7 liter.
I will use the traditional measure of 22.4 liter per mole of gas.
<u>1) Convert 14.0 g of nitrogen gas to number of moles:</u>
- n = mass in grams / molar mass
- Atomic mass of nitrogen: 14.0 g/mol
- Nitrogen gas is a diatomic molecule, so the molar mass of nitrogen gas = molar mass of N₂ = 14.0 × 2 g/mol = 28.0 g/mol
- n = 14.0 g / 28.0 g/mol = 0.500 mol
<u>2) Set a proportion to calculate the volume of nitrogen gas:</u>
- 22.4 liter / mol = x / 0.500 mol
- Solve for x: x = 0.500 mol × 22.4 liter / mol = 11.2 liter.
<u>Conclusion:</u> the volume of 14.0 g of nitrogen gas at STP is 11.2 liter.
Answer:
it is neither an acid or a base
Explanation:
Answer:
2K + HgCl2 —> Hg + 2KCl
Explanation:
K + HgCl2 —> Hg + KCl
The above equation is not balanced
To balance the equation, do the following.
First, put 2 in front of KCl, the equation becomes,
K + HgCl2 —> Hg + 2KCl
Now we see that Cl is balanced but K is not. To balance K, put 2 in front of K as shown below:
2K + HgCl2 —> Hg + 2KCl
Now we can that the equation is balanced