The formula of ozone is O3.
Hope this helps~
2 C2H2 + 5 O2 --> 4 CO2 + 2 H2O
2.35 mol C2H2 - x mol O2
2 mol C2H2 - 5 mol O2
answer: 5.875 mol
Answer:
The concentration of energy needed to withdraw an electron from an atom’s mole in the gas phase is known as the ionization energy of an atom. It is more accurately termed as the first ionization energy. The ionization energy upsurges from left to right through a period and from top to bottom in the groups.
Of the given elements S, Ca, F, Rb, and Si, the S, and Si belong to the third period, and the atomic radius of S is less in comparison to Si, F belongs to the second period, Rb belongs to the fifth period, and Ca belongs to the fourth period. Thus, the decreasing order of first ionization energy, that is, from largest to smallest is F > S > S > Ca > Rb.
Don't you think that element is ferrous i mean iron.
Answer:
The answer to your question is below
Explanation:
For the reaction N2 + 3H2 = 2NH3, if you have 2.00 moles of N2 and 4.00 moles of H2 : a. Identify the limiting reactant. ____________
N2 + 3H2 = 2NH3
1 mol 3 moles 2 moles
Given 2 moles 4 moles
Rule of three for N2
x = (2 x 3) / 1 = 6 mol of H2, it means that is needed 6 moles of H2 and there are only 4, so the limiting reactant is H2
b. How many moles of NH3 can be formed? ____________
rule of three
3 moles of H2 --------------------- 2 moles of NH3
4 moles of H2 --------------------- x
x = (4x2)/3 = 2.7 moles of NH3 are formed
c. How many moles of the excess reactant will remain? _________
x = (4 x 1) / 3 = 1.33
Excess reactant = 2 - 1.33 = 0.67 moles
