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3 years ago

How much energy is released when 50.00 mol of glycerin melts? (Heat of fusion glycerin-91.7 KJ/mol)

Chemistry

1 answer:

Irina-Kira [14]3 years ago

3 0

Answer:

4585 KJ

Explanation:

Data obtained from the question. This includes following:

Number of mole (n) of glycerin = 50 moles

Heat of fusion glycerin (Hf) = 91.7 KJ/mol

Heat (Q) released =?

The heat released can be obtained as follow:

Q = n•Hf

Q = 50 x 91.7

Q = 4585 KJ

Therefore, 4585 KJ of heat is released.

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What is the net force of 4N 2N!!

RSB [31]

Answer: 4 N-2 N=2 Nto the left. Change in motion: The box will move to the left. 7.)

Explanation: Please mark branliest.

8 0

3 years ago

Una disolución contiene 40% de ácido acético en masa. La densidad de la disolución es de 1.049 g/mL a 20°C. Calcule la masa de á

s344n2d4d5 [400]

Answer:

52.45g

Explanation:

The computation of the mass of pure acetic acid in 125mL of this solution is shown below:

The percentage of mass would be equivalent to the g of solute in each 100g of water

As we know that

density = mass ÷ volume

So,

Volume = mass ÷ density

V = 100g / 1.049 (g / ml)

V = 95.328 mL

Now In every 95,328 ml of C_2H_4O_2 there are 40g of C_2H_4O_2

i.e.

each 125ml of C_2H_4O_2 there are 52.45g

SO,

x = 40g. 125ml ÷ 95.328

x = 52.45g

4 0

3 years ago

a) What substances are present in an aqueous buffer composed of HC2H3O2 and C2H3O2 - ?b) What happens when LiOH is added to a bu

Alex17521 [72]

Answer:

a) HC₂H₃O₂, C₂H₃O₂⁻, H₃O⁺, H₂O, OH⁻

b) HC₂H₃O₂ + LiOH ⇄ H₂O + LiC₂H₃O₂

c) C₂H₃O₂⁻ + HBr ⇄ HC₂H₃O₂ + Br⁻

Explanation:

a) In a HC₂H₃O₂/C₂H₃O₂⁻ buffer system, the following reactions take place:

HC₂H₃O₂ + H₂O ⇄ C₂H₃O₂⁻ + H₃O⁺

C₂H₃O₂⁻ + H₂O ⇄ HC₂H₃O₂ + OH⁻

Thus, the species present are: HC₂H₃O₂, C₂H₃O₂⁻, H₃O⁺, H₂O, OH⁻.

b) When LiOH is added to the buffer system, it is partially neutralized according to the following equation.

HC₂H₃O₂ + LiOH ⇄ H₂O + LiC₂H₃O₂

c) When HBr is added to the buffer system, it is partially neutralized according to the following equation.

C₂H₃O₂⁻ + HBr ⇄ HC₂H₃O₂ + Br⁻

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3 years ago

How many moles is 3.85 x 1025 atoms of gold?

IrinaK [193]

Answer:

64.17 Moles of Au

Explanation:

(atoms and particles are the same)

3.85 x 10 ^25 x (1 mol

/6.02 x 10^23)

3.85 / 6 = .64166

.6416 x 10^2 = 64.166

If you round up the answer you will get 64.17

64.17 moles of Au

4 0

3 years ago

Read 2 more answers

Why does a high temperature have to be used to weld pieces of metal together

bazaltina [42]

because of the metling point of metals, it is difficult to just simply put metal together and have them to stay together without any type of glue or epoxy based creams.

wielding is used to melt the surface or even change the compound completely so they are able to combine with other metals.

same thing with atoms, you need a lot of heat, and speed to simply make salt or even copper because of the elements not really being favorable of each other.

8 0

3 years ago