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max2010maxim [7]
3 years ago
14

How much energy is released when 50.00 mol of glycerin melts? (Heat of fusion glycerin-91.7 KJ/mol)

Chemistry
1 answer:
Irina-Kira [14]3 years ago
3 0

Answer:

4585 KJ

Explanation:

Data obtained from the question. This includes following:

Number of mole (n) of glycerin = 50 moles

Heat of fusion glycerin (Hf) = 91.7 KJ/mol

Heat (Q) released =?

The heat released can be obtained as follow:

Q = n•Hf

Q = 50 x 91.7

Q = 4585 KJ

Therefore, 4585 KJ of heat is released.

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Copper has a specific heat of 0.385 J/gºC.
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Answer:

The final temperature is 348.024°C.

Explanation:

Given data:

Specific heat of copper = 0.385 j/g.°C

Energy absorbed = 7.67 Kj (7.67×1000 = 7670 j)

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Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

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Q = m.c. ΔT

Q = amount of heat absorbed or released

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7670 J / 23.87 j/°C = T2- 26.7 °C

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T2 = 321.324°C + 26.7 °C

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The final temperature is 348.024°C.

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