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2 years ago

Compared to CH4,NH3 has:

Chemistry

1 answer:

vitfil [10]2 years ago

3 0

a) NH₃ molecules have stronger intermolecular attractions than CH₄ molecules.

Explanation:

Ammonia molecules have stronger intermolecular attractions compared to methane.

Ammonia molecules have london dispersion forces and hydrogen bonds between their molecules.

Methane molecules have only london dispersion forces in their structure.

hydrogen bonds are very strong attractive forces between molecules in which the hydrogen of a molecule is attracted by a more electronegative atom of another usually oxygen, nitrogen and fluorine.
London dispersion forces are weak forces of attraction between heteronuclear atoms.

Learn more:

Hydrogen bonds brainly.com/question/10602513

#learnwithBrainly

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How many moles are in 1.51x10^26 atoms of xenon (Xe)? Please and thank you :)!!

RoseWind [281]

<h3>Answer:</h3>

251 mol Xe

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 1.51 × 10²⁶ atoms Xe

[Solve] moles Xe

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

[DA] Set up: $\displaystyle 1.51 \cdot 10^{26} \ atoms \ Xe(\frac{1 \ mol \ Xe}{6.022 \cdot 10^{23} \ atoms \ Xe})$
[DA] Multiply/Divide [Cancel out units]: $\displaystyle 250.747 \ mol \ Xe$

<u>Step 4: Check</u>

<em>Follow sig fig rule and round. We are given 3 sig figs.</em>

250.747 mol Xe ≈ 251 mol Xe

3 0

2 years ago

Find the mass of 1.112 moles HF?

Alexeev081 [22]

Answer:

22.25 g

Explanation:

To find the mass, you need to convert moles to grams and get 22.25 g.

7 0

2 years ago

What type of bond would form between two atoms of selenium? A. Double ionic bond B. Single ionic bond C. Single covalent bond D.

kirill115 [55]

The corret answer is D

3 0

3 years ago

There are three naturally occurring isotopes of the hypothetical element hilarium 45Hi, 46Hi, and 48Hi. The percentages of these

den301095 [7]

Answer:

46.761g/mol

Explanation:

Given parameters:

Element = Hilarium , Hi

Isotopes: Hi- 45, Hi-46 and Hi- 48

Natural abundance of Hi-45 = 18.3%

Hi-46 = 34.5%

Hi-48 = 47.2%

Unknown:

Atomic weight of naturally occurring Hilarium = ?

Solution:

Isotopes have been studied extensively by mass spectrometry. The method is used to determine the proportion/percentage/fraction by which each of the isotopes of an element occurs in nature. The proportion is called geonormal abundance. From this we can calculate the atomic weight of an element.

We can use the expression below to find this value:

Atomic weight = m₄₅α₄₅ + m₄₆α₄₆ + m₄₈α₄₈

m is the atomic mass of each isotope and α is the abundance

Atomic weight = (45 x $\frac{18.3}{100}$ ) + (46 x $\frac{34.5}{100}$ ) + (48 x $\frac{47.2}{100}$ )

Atomic weight of Hi = 8.235 + 15.870 + 22.656 = 46.761g/mol

6 0

2 years ago

which of the following would a chemist be most likely to study? a. a leaf floating on water c. a leaf being blown by the wind b.

Salsk061 [2.6K]

I think the correct answer from the choices listed above is option B. It would be a leaf changing color in autumn <span>would a chemist be most likely to study. A chemist should be more interested in processes that chemical reactions are most likely to occur and changes in color can be one of the indications of such reactions.</span>

6 0

2 years ago