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S_A_V [24]
3 years ago
9

Compared to CH4,NH3 has:

Chemistry
1 answer:
vitfil [10]3 years ago
3 0

a) NH₃ molecules have stronger intermolecular attractions than CH₄ molecules.

Explanation:

Ammonia molecules have stronger intermolecular attractions compared to methane.

Ammonia molecules have london dispersion forces and hydrogen bonds between their molecules.

Methane molecules have only london dispersion forces in their structure.

  • hydrogen bonds are very strong attractive forces between molecules in which the hydrogen of a molecule is attracted by a more electronegative atom of another usually oxygen, nitrogen and fluorine.
  • London dispersion forces are weak forces of attraction between heteronuclear atoms.

Learn more:

Hydrogen bonds brainly.com/question/10602513

#learnwithBrainly

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What is the specific heat of a substance if 1560 cal are required to raise the temperature of a 312-g sample by 15°C?
Oksanka [162]
The specific heat capacity  the substance is calculated  using  the below formula

Q(heat) = Mc delta T
Q =1560  cal
m(mass) 312 g
delta T (change in temperature ) = 15 c
C= specific heat capacity=?

by making c the subject of the formula 
c=Q/m delta T
= 1560  cal/ 312g x 15 c = 0.33 cal/g/c (answer B)


8 0
3 years ago
What happens when the thermal energy of a substance increases?
MariettaO [177]

Answer:

Explanation:

Both motion of particles and temperature increase

8 0
3 years ago
Read 2 more answers
How many formula units are present in 40.0 grams of Cu2S?
11Alexandr11 [23.1K]

Never mind, I did the problem wrong, I deeply apologize.

4 0
2 years ago
Gold has a density of 1,200 lb./ft. What is the density of gold in g/em? For conversion factors use I lb. 453.6 g, and l inch-2.
Jlenok [28]

<u>Answer:</u> The density of gold in g/cm^3 is 19.22g/cm^3

<u>Explanation:</u>

Density is defined as the ratio of mass of the object and volume of the object. Mathematically,

\text{Density}=\frac{\text{Mass of the object}}{\text{Volume of the object}}

We are given:

Density of gold = 1200lb/ft^3

Using conversion factors:

1 lb = 453.6 g

1 feet = 12 inches

1 inch = 2.54 cm

Converting given quantity into g/cm^3, we get:

\Rightarrow (\frac{1200lb}{ft^3})\times (\frac{453.6g}{1lb})\times (\frac{1ft}{12inch})^3\times (\frac{1inch}{2.54cm})^3\\\\\Rightarrow 19.22g/cm^3

Hence, the density of gold in g/cm^3 is 19.22g/cm^3

6 0
3 years ago
Write the balanced chemical equation between H2SO4H2SO4 and KOHKOH in aqueous solution. This is called a neutralization reaction
const2013 [10]

Answer:

0.185M sulfuric acid

Explanation:

Based on the reaction:

H₂SO₄ + 2KOH → K₂SO₄ + 2H₂O

<em>1 mole of sulfuric acid reacts with 2 moles of KOH</em>

Initial moles of H₂SO₄ and KOH are:

H₂SO₄: 0.750L ₓ (0.470mol / L) = <em>0.3525 moles of H₂SO₄</em>

KOH: 0.700L ₓ (0.240mol / L) = <em>0.168 moles of KOH</em>

The moles of sulfuric acis that react with KOH are:

0.168mol KOH ₓ (1 mole H₂SO₄ / 2 moles KOH) = 0.0840 moles of sulfuric acid.

Thus, moles that remain are:

0.3525moles - 0.0840 moles = <em>0.2685 moles of sulfuric acid remains</em>

As total volume is 0.700L + 0.750L = 1.450L, concentration is:

0.2685mol / 1.450L = <em>0.185M sulfuric acid</em>

8 0
3 years ago
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