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jonny [76]
2 years ago
15

When heated, allyl aryl ethers and allyl vinyl ethers undergo a reaction called a Claisen rearrangement, a concerted reorganizat

ion of bonding electrons similar to the Diels-Alder reaction. The reaction proceeds through a six-membered, cyclic transition state.Draw the structure of the expected product when this compound undergoes a Claisen rearrangement.For the purposes of this problem, assume that double bonds in an aromatic ring are localized at the positions indicated in the figure

Chemistry
1 answer:
mario62 [17]2 years ago
8 0

In this case, we assume that the starting compound is phenol which become in phenoxide due to reaction with sodium hydride. Sodium ohenoxide reacts with 3-bromo-1-propene to obtain the allyl aryl ether: allyl phenylether.

The allyl aryl ether undergoes Claisen reanrrangement when is heat between 200 and 250 celsius grades obtaining o-allyl phenol.

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A 25.0 ml sample of 0.150 m hydrazoic acid is titrated with a 0.150 m naoh solution. what is the ph after 15.0 ml of the sodium
babunello [35]
First, we need to calculate moles of hydrazoic acid NH3:

moles NH3 = molarity * volume 

                    = 0.15 m * 0.025 L

                   =  0.00375 moles

moles NaOH = molarity * volume 

                       = 0.15 m * 0.015 L

                       = 0.00225 moles 

after that we shoul get the total volume = 0.025L + 0.015L

                                                                   = 0.04 L

So we can get the concentration of NH3 & NaOH by:

∴[NH3] = moles NH3 / total volume 

           = 0.00375 moles / 0.04 L

           = 0.09375 M

∴[NaOH] = moles NaOH / total volume 

                = 0.00225 moles / 0.04 L

                = 0.05625 M

then, when we have the value of Ka of NH3 so we can get the Pka value from:

Pka = -㏒Ka 

       = - ㏒ 1.9 x10^-5

      = 4.7 

finally, by using H-H equation we can get PH:

PH = Pka + ㏒[salt/ basic]

PH = 4.7 +㏒[0.05625/0.09375]

∴ PH = 4.48 


6 0
2 years ago
Do atoms lend and borrow electrons from inner shells
zaharov [31]
False. They don't borrow electrons at all. They already have their respective electron affinities. This is called as electronegativity, and it's an occurence where it already has its own from its actual structure. It never borrows any electrons at all.
4 0
3 years ago
Explain why 1 mole of diethyl ether requires less heat to
gizmo_the_mogwai [7]

The quantity of heat required to vapourize 1 mole of a substance depends on the kind of intermolecular forces between the molecules of the substance. Diethyl ether molecules are held together by weak dispersion forces compared to the stronger hydrogen bonding in ethanol. Therefore,  1 mole of diethyl ether requires less heat to  vapourize than is required to vapourize 1 mole of  ethanol.

Intermolecular forces hold the molecules a substance together in a given state of matter. The properties of a substance such as boiling point, melting point etc are dependent on the nature of intermolecular forces holding the molecules of the substance.

Diethyl ether molecules are held together by weak dispersion forces while molecules of ethanol are held together by hydrogen bonds.

Since hydrogen bonds are much stronger than dispersion forces, a greater quantity of heat is required to break the intermolecular hydrogen bonds in ethanol in order to vapourize them than is required to vapourize diethyl ether.

Therefore, owing to stronger intermolecular forces between molecules of ethanol, less heat is required to vapourize than is required to vapourize 1 mole of  ethanol.

Learn more: brainly.com/question/9328418

6 0
3 years ago
Which of the following metals may tarnish to a greenish-blue color called verdigris
hoa [83]
Copper. thats the way copper oxidized. like the statue of liberty 
3 0
3 years ago
Read 2 more answers
If a chemist has a stock solution of HBr that is 10.0 M and would like to make 450.0 mL of 3.0 M HBr, how would he do it?
asambeis [7]

This is a dilution that requires a certain volume from the stock solution to be diluted with distilled water to make a solution of HBr with a lesser concentration than the stock solution

Following dilution formula can be used

c1v1 = c2v2

Where c1 is concentration and v1 is the volume of the stock solution

c2 is concentration and v2 is volume of the diluted solution to be prepared

Substituting these values

10.0 M x v1 = 3.0 x 450.0 mL

v1 = 135.0 mL

A volume of 135.0 mL from HBr stock solution needs to be taken and diluted with distilled water upto 450.0 mL. The resulting solution will have a concentration of 3.0 M

4 0
2 years ago
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