2 years ago

12 more than quotient of a number k and 5

Mathematics

1 answer:

Harman [31]2 years ago

8 0

Answer:

(k/5)+12 represents the question described

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Solve the equation for x.

valentina_108 [34]

Answer:

Solve for

by simplifying both sides of the equation, then isolating the variable.

Exact Form:

5 /4

Decimal Form:

1.25

Mixed Number Form:

1 1/4

Step-by-step explanation:

THE ANSWER IS C

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2 years ago

What is the base 10 number of 60 +3?

Sauron [17]

60 is the base OK. I think am right

3 0

2 years ago

Solve this equation please ! −2 − (+7) = ?

olga55 [171]

-2 - (+7) =
-2 - 7 =
-9
<3

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3 years ago

Determine whether the given lengths can be sides of a right triangle. Which of the following are true statements. A.The lengths

Stels [109]

Answer:

Given sides 12, 16 and 20 can be the sides of right triangle.

Step-by-step explanation:

Sides of right triangle always follow the Pythagoras theorem.

i.e $(base)^2 + (Height)^2 = (Hypotenuse)^2$

For the given Lengths 7, 40 and 41

We need to check if

$7^2 + 40^2 =41^2 \\or\\ 7^2 + 40^2 \neq41^2$

$Since \\7^2 + 40^2 = 1649\\and \\41^2 = 1681$

That means, $\\ 7^2 + 40^2 \neq 41^2$

hence 7,40 and 41 can not be the sides of right triangle.

Next,

Given sides 12,16 and 20.

Again follow the similar process used in the above problem.

$12^2 + 16^2 =400\\And \\20^2 = 400\\Since 12^2 + 16^2 = 20^2$

Therefore given sides 12,16 and 20 can be the sides of right triangle.

7 0

2 years ago

What is the value of the expression 4/2^-2? a. ½ b. 1 c. 8 d. 16

Alexus [3.1K]

$2^{-2} = \frac{1}{2^{2} } = \frac{1}{4}$

$\frac{4}{2^{-2} } = \frac{4}{ \frac{1}{4} } = 4$ ÷ $\frac{1}{4} = 4*4= 16$

The answer is D. 16

8 0

2 years ago