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just olya [345]
3 years ago
15

12 more than quotient of a number k and 5

Mathematics
1 answer:
Harman [31]3 years ago
8 0

Answer:

(k/5)+12 represents the question described

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One minus the quotient of one and a number x
evablogger [386]

The answer to the statement is 1/x-1.

4 0
3 years ago
Read 2 more answers
Machine A can produce 435 widget in 3 hours. At this rate how many widget can machine A produce in 7 hours?
Vesna [10]

Answer:

1015 widgets

Step-by-step explanation:

First investigate how many widgets can machine A produce in 1 hour:

If it produces 435 in 3 hours, then it will produce one third of that in one hour:

In ONE (1) hour \frac{435}{3} = 145 widgets

Therefore in seven (7) hours it will produce seven times the amount it does in one hour, that is:

145 * 7 = 1015 widgets

3 0
3 years ago
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PLEASE HELP
Nookie1986 [14]

For the square with side length n, the diagonal measures:

d = \sqrt{2} *n

<h3>How to get the length of the diagonal?</h3>

The sidelength of the square is n, and we want to get the length of the diagonal d.

Notice that the diagonal is the hypotenuse of a right triangle whose catheti measure n.

Then we can use the Pythagorean theorem, which says that the square of the hypotenuse is equal to the sum of the squares of the cathetus;

d^2 = n^2 + n^2\\\\d^2 = 2n^2\\\\d = \sqrt{2n^2} \\\\d = \sqrt{2}*n

That is the length of the diagonal.

If you want to learn more about right triangles:

brainly.com/question/2217700

#SPJ1

6 0
2 years ago
the graph shows that lisa's earnings are proportional to the number of hours that she works.This relationship can be represented
Annette [7]

c. 25 because she gets $25 per hour

3 0
3 years ago
A bag contains marbles: 5 red, 2 blue, and 1 green. You pick a marble and then another one without replacement. What is the prob
max2010maxim [7]

hi

1st draw: green

2/12. (2 green out of 12 marbles), reduces to 1/6

2nd draw: blue

4/11 (4 blue marbles out of the 11 marbles remaining after 1st draw.)

Probability of theses BOTH happening: multiply these individual probabilities.

Conditional probability:

P(a and b) = P(a)P(b|a)

Prob(event 1) × Prob(event 2 given event 1).

1/6 • 4/11 = 4/66 = 2/33 or 0.0606. just a hair over 6% probability of the described sequence hapening.

5 0
2 years ago
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