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3 years ago

Can somebody help me with this please ?? :)

Mathematics

1 answer:

Tresset [83]3 years ago

4 0

yes they are congruent budy because they have given AC is equal to AD,, BC is equal to ED and angle BAC is equal to angle EAD.

For congruence of triangle ABC and triangle ADE we just need three parts that we got and therefore they are congruent..

don't forget to follow

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Kelly has a rectangular fish aquarium that

Hoochie [10]

Volume = 18x8x12
= 1728

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3 years ago

Differentiate 6+4x - x^2

vfiekz [6]

Answer:

2x+4

Step-by-step explanation:

hope that helps

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2 years ago

Find the differential coefficient of <br><img src="https://tex.z-dn.net/?f=e%5E%7B2x%7D%281%2BLnx%29" id="TexFormula1" title="e^

Gemiola [76]

Answer:

$\rm \displaystyle y' = 2 {e}^{2x} + \frac{1}{x} {e}^{2x} + 2 \ln(x) {e}^{2x}$

Step-by-step explanation:

we would like to figure out the differential coefficient of $e^{2x}(1+\ln(x))$

remember that,

the differential coefficient of a function y is what is now called its derivative y', therefore let,

$\displaystyle y = {e}^{2x} \cdot (1 + \ln(x) )$

to do so distribute:

$\displaystyle y = {e}^{2x} + \ln(x) \cdot {e}^{2x}$

take derivative in both sides which yields:

$\displaystyle y' = \frac{d}{dx} ( {e}^{2x} + \ln(x) \cdot {e}^{2x} )$

by sum derivation rule we acquire:

$\rm \displaystyle y' = \frac{d}{dx} {e}^{2x} + \frac{d}{dx} \ln(x) \cdot {e}^{2x}$

Part-A: differentiating $e^{2x}$

$\displaystyle \frac{d}{dx} {e}^{2x}$

the rule of composite function derivation is given by:

$\rm\displaystyle \frac{d}{dx} f(g(x)) = \frac{d}{dg} f(g(x)) \times \frac{d}{dx} g(x)$

so let g(x) [2x] be u and transform it:

$\displaystyle \frac{d}{du} {e}^{u} \cdot \frac{d}{dx} 2x$

differentiate:

$\displaystyle {e}^{u} \cdot 2$

substitute back:

$\displaystyle \boxed{2{e}^{2x} }$

Part-B: differentiating ln(x)•e^2x

Product rule of differentiating is given by:

$\displaystyle \frac{d}{dx} f(x) \cdot g(x) = f'(x)g(x) + f(x)g'(x)$

let

$f(x) \implies \ln(x)$
$g(x) \implies {e}^{2x}$

substitute

$\rm\displaystyle \frac{d}{dx} \ln(x) \cdot {e}^{2x} = \frac{d}{dx}( \ln(x) ) {e}^{2x} + \ln(x) \frac{d}{dx} {e}^{2x}$

differentiate:

$\rm\displaystyle \frac{d}{dx} \ln(x) \cdot {e}^{2x} = \boxed{\frac{1}{x} {e}^{2x} + 2\ln(x) {e}^{2x} }$

Final part:

substitute what we got:

$\rm \displaystyle y' = \boxed{2 {e}^{2x} + \frac{1}{x} {e}^{2x} + 2 \ln(x) {e}^{2x} }$

and we're done!

6 0

3 years ago

What is the value of x in equation 0.2(x+1)+ 0.5x = - 0.3(x-4)

Greeley [361]

Answer: x=1

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

A local bakery has a daily operating cost of $1800 plus a cost of $10 per cake

Delicious77 [7]

Answer:

B. 15c > 1,800 + 10c

Step-by-step explanation:

Profit=Total revenue - total cost

Profit is achieved:

when total revenue is greater than total cost

TR>TC

When total cost is less than total revenue

TC<TR

From the question

Total cost=1800+10c

Total revenue=15c

Profit=TR>TC or TC<TR

15c>1800+10c

1800+10c<15c

Option B. 15c > 1,800 + 10c satisfies the condition that Profit=TR>TC

4 0

3 years ago

Read 2 more answers