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tester [92]
3 years ago
10

What is the correct equilibrium constant

Chemistry
1 answer:
Ksju [112]3 years ago
6 0

Answer:

(CO2)+(CF)/ (COF)².

Explanation:

k=

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Answer: 61.3 g of H_2O will be produced from the given masses of both reactants.

Explanation:

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

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b) moles of O_2

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4NH_3+5O_2\rightarrow 4NO+6H_2O

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As 5 moles of O_2 give =  6 moles of H_2O

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Mass of H_2O=moles\times {\text {Molar mass}}=3.41moles\times 18g/mol=61.3 g

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