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3 years ago

What is the correct equilibrium constant

Chemistry

1 answer:

Ksju [112]3 years ago

6 0

Answer:

(CO2)+(CF)/ (COF)².

Explanation:

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Tarnish on copper is the compound CuO. A tarnished copper plate is placed in an aluminum pan of boiling water. When enough salt

oksian1 [2.3K]

Answer:

The standard cell potential is 2.00 V

Explanation:

Step 1: Data given

Cu is cathode because of higher EP

Al3++3e−→Al E∘=−1.66 V anode

Cu2++2e−→Cu E∘=0.340 V cathode

Step 2: Balance both equations

2*(Al → Al3+-3e−) E∘=1.66 V

3*(Cu2++2e−→Cu) E∘=0.340 V

Step 3: The netto equation

2 Al + 3Cu2+ +6e- → 2Al3+ + 3Cu -6e-

2 Al + 3Cu2+ → 2Al3+ + 3Cu

Step 4: Calculate the standard cell potential

E∘cell = E∘cathode - E∘anode

E∘cell = E∘ Cu2+/Cu - E∘ Al3+/Al

E∘cell =0.340 V - (-1.66) = 2.00 V

The standard cell potential is 2.00 V

4 0

2 years ago

How many grams of sulfur are needed to react completely with 246 g of mercury to form hgs?

iren [92.7K]

The reaction between mercury (Hg) and sulfur (S) to form HgS is:

Hg + S ------------- HgS

Therefore: 1 mole of Hg reacts with 1 mole of S to form 1 mole of HgS

The given mass of Hg = 246 g

Atomic mass of Hg = 200.59 g/mol

# moles of Hg = 246 g/ 200.59 gmol-1 = 1.226 moles

Based on the reaction stoichiometry,

# moles of S that would react = 1.226 moles

Atomic mass of S = 32 g/mol

Therefore, mass of S = 1.226 moles*32 g/mole = 39.23 g

39.2 g of sulfur would be needed to react completely with 246 g of Hg to produce HgS

5 0

2 years ago

Read 2 more answers

What is the pH of .0003 M of NaOH

s344n2d4d5 [400]

We are given that the concentration of NaOH is 0.0003 M and are asked to calculate the pH

We know that NaOH dissociates by the following reaction:

NaOH → Na⁺ + OH⁻

Which means that one mole of NaOH produces one mole of OH⁻ ion, which is what we care about since the pH is affected only by the concentration of H⁺ and OH⁻ ions

Now that we know that one mole of NaOH produces one mole of OH⁻, 0.0003M NaOH will produce 0.0003M OH⁻

Concentration of OH⁻ (also written as [OH⁻]) = 3 * 10⁻⁴

pOH of the solution:

pOH = -log[OH⁻] = -log(3 * 10⁻⁴)

pOH = -0.477 + 4

pOH = 3.523

pH of the solution:

We know that the sum of pH and pOH of a solution is 14

pH + pOH = 14

pH + 3.523 = 14 [subtracting 3.523 from both sides]

pH = 10.477

8 0

3 years ago

2 Ag20 →4 Ag + O2 what reaction is this

Schach [20]

Answer:

Decomposition

Explanation:

hope it helps you

6 0

3 years ago

Gimme ur bath water plzzzz

kari74 [83]

Answer:

plzz can you explain in detail this Q

6 0

3 years ago