The metal you can insert in aqueous solution of cobalt(ii) nitrate and displace cobalt is zinc.
<h3>Electrochemical series</h3>
Electrochemical series is as know as reactivity series. The electrochemical series list metals in order of decreasing reactivity.
Generally, metals higher up in the series than cobalt metal will displace cobalt(ii) ions from it solution and produce cobalt metal. Therefore, Metals like Zinc will displace cobalt(ii) form it compound.
The reaction with a solution of cobalt (II) nitrate can be represented as follows:
Co(NO₃)₂ + Zn → Zn(NO₃)₂ + Co
learn more on displacement here: brainly.com/question/6462267
Explanation:
Features of Mendeleev's tables
Mendeleev arranged the elements in order of increasing relative atomic mass . When he did this he noted that the chemical properties of the elements and their compounds showed a periodic trend .
Answer:
B
Explanation:
The attraction is stronger when the magnet is closer so moving it away would decrease the strength.
Answer:
MoO₃
Explanation:
To solve this question we must find the moles of molybdenum in Mo2O3. The moles of Mo remain constant in the new oxide. With the differences in masses we can find the mass of oxygen and its moles obtaining the empirical formula as follows:
<em>Moles Mo2O3 -Molar mass: 239,878g/mol-</em>
11.79g * (1mol / 239.878g) = 0.04915 moles Mo2O3 * (2mol Mo / 1mol Mo2O3) = 0.09830 moles Mo
<em>Mass Mo in the oxides:</em>
0.09830 moles Mo * (95.95g/mol) = 9.432g Mo
<em>Mass oxygen in the new oxide:</em>
14.151g - 9.432g = 4.719g oxygen
<em>Moles Oxygen:</em>
4.719g oxygen * (1mol/16g) = 0.2949 moles O
The ratio of moles of O/Mo:
0.2949molO / 0.09830mol Mo = 3
That means there are 3 moles of oxygen per mole of Molybdenum and the empirical formula is:
<h3>MoO₃</h3>
