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Natasha2012 [34]
3 years ago
8

What is the value of x?please help​

Mathematics
1 answer:
wlad13 [49]3 years ago
4 0
X=X but I can’t know until I see the full problem
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Write an English phrase that would translate into the following mathematical expression.
Yuliya22 [10]

Answer:

C.

Step-by-step explanation:

5z - 7, you would say 5 times z minus 7, which is the same as 5 less than th product of 7 and a number z

6 0
3 years ago
What is the range of the function?
Goryan [66]

Answer:

1. all real numbers less than or equal to 4 = </= 4.

Answer = YES!

2. all real numbers less than or equal to -3 = </= -3.

Answer = YES!

3. all real numbers greater than or equal to 4 = >/= 4

Answer = YES!

4. all real numbers greater than or equal to -3 = >/= -3

Answer = NO!

Step-by-step explanation:

1. all real numbers less than or equal to 4 = </= 4.

1 + 1 = 2

1 + 2 = 3

2 + 2 = 4

2. all real numbers less than or equal to -3 = </= -3.

1 - 1 = 0

1 - 2 = -1

1 - 3 = -2

1 - 4 = -3

3. all real numbers greater than or equal to 4

1 + 1 = 2

1 + 2 = 3

1 + 3 = 4

1 + 4 = 5

4. all real numbers greater than or equal to -3

1 - 1 = 0

1 - 2 = -1

1 - 3 = -2

1 - 4 = -3

3 0
3 years ago
HELP ASAP!!!!!!!!!!!
mario62 [17]

Answer:

I can't see the picture

Step-by-step explanation:

8 0
3 years ago
Kunal told Ana he was going to drop 10 dimes on the table. He said he would give her all the dimes where the "head" side was sho
sweet-ann [11.9K]

Answer:

10

Step-by-step explanation:

4 0
2 years ago
A computer maker receives parts from three suppliers, S1, S2, and S3. Fifty percent come from S1, twenty percent from S2, and th
rewona [7]

Answer:

a) 4.9 % of all parts is defective or 0.049 of the total parts.

b)  0.5102 is the probability that the defective part was supplied by S1

Step-by-step explanation:

N is the total number of parts from supplier S1, S2 and S3.

N1 = 0.5*N is the total number of part supplied by S1

N2 = 0.2*N is the total number of part supplied by S2  

N3 = 0.3*N is the total number of part supplied by S3

a) if Nd1 is the number of defective parts from supplier S1, Nd2 is the number of defective parts from supplier S2 and Nd3 is the number of defective parts from supplier S3, the the total defective parts Nd is:

Nd = Nd1 + Nd2 + Nd3, where

Nd1 = 0.05*N1 = 0.05*0.5*N = 0.025*N,

Nd2 = 0.03*N2 = 0.03*0.2*N = 0.006*N,

Nd3 = 0.06*N3 = 0.06*0.3*N = 0.018*N,

Then Nd = Nd1 + Nd2 + Nd3 =  0.049*N, so Nd/N = 0.049

b) P(S1 \vert d) = \frac{P(S1,d)}{P(d)} = \frac{P(d \vert S1)}{P(d)} = \frac{0.05*0.5}{0.049} \approx 0.5102

for the last expression I used the Bayes tehorem.

P(S1 \vert d) is the probability that occur S1 given that d (defective) is true. This a conditional probability.

see at https://en.wikipedia.org/wiki/Bayes%27_theorem

6 0
3 years ago
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