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zalisa [80]
3 years ago
15

A 8.5 L sample is collected at 45°C. What will the volume be if the temperature is raised to 70°C? End of exam A. 9.2 L B. 13.2

L C. 7.9 L D. 5.5 L
Chemistry
1 answer:
klasskru [66]3 years ago
7 0

Answer: The correct option is A.

Explanation: To calculate the volume at the end , we use Charles's Law, which states that the volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

V\propto T

or

\frac{V_1}{T_1}=\frac{V_2}{T_2}

  • Initial conditions:

V_1=8.5L

T_1=45^oC=(45+273)K=318K

  • Final conditions:

V_2=?L

T_2=70^oC=(70+273)K=343K

Putting all the values in above equation, we get

\frac{8.5}{318}=\frac{V_2}{343}

V_2=9.2L

Hence, the correct option is A.

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Answer:50 ml ☺️

Explanation:

7 0
3 years ago
Please help!!!!its due tomorrow !!!
scZoUnD [109]

#6).
Every 1,000 mL makes 1 L
How many 1,000mL are there in  2,800 mL ?
That's division.
                         (2,800 mL) / (1,000 mL) = <em>2.8 L</em>

#7).
The 'perimeter' means the 'distance all the way around'.
You have to know that both sides of a rectangle are the same length,
and also the top and bottom are the same length.
So the perimeter of this rectangle is

   (2 yd) + (4.5 yd) + (2.yd) + (4.5 yd) = 13 yd .

Oops.  The problem wants to know the perimeter in feet.
So you have to know that each yard is the same as 3 feet.
In order to find the number of feet in 13 yards, you have to
take 3 feet 13 <em><u>times</u></em> .

       (3 feet) times (13)  =  <em>39 feet .</em>

#8).
For this one, you have to know that every 36 inches makes 1 yard.

How many 36 inches are there in 48 inches ?
That's division.
                         (48 inches) / (36inches)  =  <em>1 and 1/2 yards</em> .

#9).
For this problem, you have to know how to handle a mixed number,
and you also have to know that there are 16 ounces in 1 pound.

Add up the fruit:

             (3-1/2 pounds) + (4 pounds) + 2 pounds)  =  <em><u>9-1/2 pounds</u></em>

Now, remember that each pound is the same as 16 ounces.  So if you
want to find the number of ounces in  9-1/2 pounds, you have to take
16 ounces  9-1/2 times .

     (16 ounces) times (9-1/2) = <em>152 ounces</em>.
___________________________________

#10).
This one is just adding up some numbers.  But after you finish doing that, you have to know that  1,000 meters is called '1 kilometer' .

Add up the distances that Omar ran:

   (1,000 meters) + (1,625 meters) + (1,500 meters)  =  <em><u>4,125 meters</u></em>

The problem wants to know how many kilometers this is, so you have to figure out how many '1,000 meters' fit into 4,125 meters.

That's division.

   (4,125 meters) / (1,000 meters)  =  <em>4.125 kilometers</em>


4 0
4 years ago
The naturally occurring radioactive decay series that begins with 23592U stops with formation of the stable 20782Pb nucleus. The
dsp73

Answer: There are 7 alpha-particle emissions and 4 beta-particle emissions involved in this series

Explanation:

Alpha Decay: In this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. The mass number is reduced by 4 units and atomic number is reduced by 2 units.

Beta Decay : It is a type of decay process, in which a proton gets converted to neutron and an electron. This is also known as -decay. In this the mass number remains same but the atomic number is increased by 1.

In radioactive decay the sum of atomic number or mass number of reactants must be equal to the sum of atomic number or mass number of products .

_{92}^{235}\textrm{U}\rightarrow _{82}^{207}\textrm{Pb}+X_2^4\alpha+Y_{-1}^0e

Thus for mass number : 235 = 207+4X

4X= 28

X = 7

Thus for atomic number : 92 = 82+2X-Y

2X- Y = 10

2(7) - Y= 10

14-10 = Y

Y= 4

_{92}^{235}\textrm{U}\rightarrow _{82}^{207}\textrm{Pb}+7_2^4\alpha+4_{-1}^0e

Thus there are 7 alpha-particle emissions and 4 beta-particle emissions involved in this series

3 0
3 years ago
(8.6 1029) 7.4 X1029)
andrew11 [14]

Answer:

65563.914234

Explanation:

8.61029 x 7.4 x 1029

63.716146 x 1029

multiply

= 65563.914234

3 0
3 years ago
Read 2 more answers
1. Name the compound present in a sample of dry air.
aev [14]

Answer:

not air

Explanation:

I think so

hahaha

7 0
2 years ago
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