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Murljashka [212]
4 years ago
8

In many cartoon shows, a character runs off a cliff, realizes his predicament, and lets out a scream. He continues to scream as

he falls. If the physical situation is portrayed correctly, from the vantage point of an observer at the top of the cliff leaning over the edge, the pitch of the scream as he falls should be In many cartoon shows, a character runs off a cliff, realizes his predicament, and lets out a scream. He continues to scream as he falls. If the physical situation is portrayed correctly, from the vantage point of an observer at the top of the cliff leaning over the edge, the pitch of the scream as he falls should be
a. lower than the original pitch and constant.
b. higher than the original pitch and increasing as he falls.
c. higher than the original pitch and constant.
d. lower than the original pitch and decreasing as he falls.
e. It is impossible to predict.
Physics
1 answer:
Naddik [55]4 years ago
8 0

Answer:

d. lower than the original pitch and decreasing as he falls.

Explanation:

As per the Doppler effect when the pitch of the sound increases as the source approaches the observer and decreases as the source moves away. A classic example of this increasing pitch of ambulance siren as it approaches you and decreasing pitch of the siren as it goes away from you.

The same effect is applicable here as well. As the character keep falling, it is moving away from the observer so the pitch of his scream will keep on decreasing.

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6 0
3 years ago
A ball is thrown upward with a speed of 28.2 m/s.A. What is its maximum height?B. How long is the ball in the air?C. When does t
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Answer:

(A) The maximum height of the ball is 40.57 m

(B) Time spent by the ball on air is 5.76 s

(C) at 33.23 m the speed will be 12 m/s

Explanation:

Given;

initial velocity of the ball, u = 28.2 m/s

(A) The maximum height

At maximum height, the final velocity, v = 0

v² = u² -2gh

u² = 2gh

h = \frac{u^2}{2g}\\\\h = \frac{(28.2)^2}{2*9.8}\\\\h = 40.57 \ m

(B) Time spent by the ball on air

Time of flight = Time to reach maximum height + time to hit ground.

Time to reach maximum height = time to hit ground.

Time to reach maximum height  is given by;

v = u - gt

u = gt

t = \frac{u}{g}

Time of flight, T = 2t

T = \frac{2u}{g}\\\\ T = \frac{2*28.2}{9.8}\\\\ T = 5.76 \ s

(C) the position of the ball at 12 m/s

As the ball moves upwards, the speed drops, then the height of the ball when the speed drops to 12m/s will be calculated by applying the equation below.

v² = u² - 2gh

12² = 28.2² - 2(9.8)h

12² - 28.2² = - 2(9.8)h

-651.24 = -19.6h

h = 651.24 / 19.6

h = 33.23 m

Thus, at 33.23 m the speed will be 12 m/s

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3 years ago
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Answer:

The amount of potential energy that was initially stored in the spring is 88.8 J.

Explanation:

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Coefficient of kinetic friction = 0.50

We need to calculate the amount of potential energy

Using formula of conservation of energy between point A and B

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Put the value into the formula

U_{A}=0.50\times1.60\times9.8\cos30\times6.55+1.60\times9.8\times6.55\sin30+\dfrac{1}{2}\times1.60\times(7.50)^2

U_{A}=88.8\ J

Hence, The amount of potential energy that was initially stored in the spring is 88.8 J.

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