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katovenus [111]
3 years ago
9

The Coefficient of kinetic friction between the tires of your car and the roadway is \"μ\". (a) If your initial speed is \"v\" a

nd you lock your tires during breaking, how far do you skid? (b) What is the stopping distance for a truck with twice the mass of you car, assuming same initial speed and coefficient of kinetic friction.. . I'm stuck on (b), my mass cancels out every time, but that doesn't seem right
Physics
2 answers:
vazorg [7]3 years ago
3 0
We make use of the equation: v^2=v0^2+2a Δd. We substitute v^2 equals to zero since the final state is halting the truck. Hence we get the equation           -<span>v0^2/2a = Δd. F = m a from the second law of motion. Rearranging, a = F/m
</span>F = μ Fn where the force to stop the truck is the force perpendicular or normal force multiplied by the static coefficient of friction. We substitute, -v0^2/2<span>μ Fn/m</span> = Δd. This is equal to 
Hatshy [7]3 years ago
3 0

Answer:

a) stopping distance = (v^2 / 2*g*μ)

b) stopping distance = (v^2 / 2*g*μ)  

Explanation:

We will use the constant acceleration formula

u^2 = v^2 + 2*a*s    ------- (1)

  • u is the final velocity (m/s)
  • v is the initial velocity (m/s)
  • a is the acceleration (m/s^2)
  • s is the stopping distance (m/s)

Acceleration can be determined from the 2nd Law of motion

F = m*a ------- (2)

  • F is the force to stop the car/truck (N)
  • m is the mass of car (kg)

Coefficient of Friction is the ratio of applied force to the normal force, hence

μ = F/Fn ------- (3)

  • Fn is the normal force (N)

Fn = m*g ------- (4)

  • g is the gravitational acceleration (m/s^2)

Substituting equation (4) into equation (3), we get

F = m*g*μ ------- (5)

Substituting equation (5) in equation (2), we get

a = g*μ ------- (6)

Substituting equation (6) in equation (1), we get

u^2 = v^2 + 2*s*g*μ

Final velocity u is zero as the car is halting for part (a), hence

-v^2 = 2*s*g*μ

s = - ( v^2 /  2*g*μ)           SI unit is meters, m

The negative sign can be ignored as the car is decelerating (negative acceleration), so

s = (v^2 / 2*g*μ)

For part (b), we will simply substitute 2*m instead of m in the equations and carry out the same procedure as part (a). The answer that we get is the same as part (a), that is,

s = (v^2 / 2*g*μ)            SI unit is meters, m

Note: The reason we get the same answer for both the part is the fact that the stopping distance is independent of the mass. The force required to bring about truck is twice as much as that for the car but on the other hand the force generated due to friction in case of truck is also twice as much as that of the car. As all the other variables are similar, the stopping distance will be same.

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Explanation:

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When a circuit is COMPLETED when electrons can flow from one end of a battery all the way around, through the wires, to the other end of the battery. Along its way, it will carry electrons to electrical objects that are connected to it like the light bulb and make it to produce light.

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2 years ago
Benzene is a starting material in the synthesis of nylon fibers and polystyrene (styrofoam). Its specific heat capacity is 1.74
sweet-ann [11.9K]

Answer: 62.7^0C

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

Q=m\times c\times \Delta T

Q = Heat absorbed= 16.7 kJ = 16700 J  (1kJ=1000J)

m= mass of benzene = 225 g

c = specific heat capacity = 1.74 J/gK

Initial temperature of the water = T_i = 20.0°C  = 293 k  0^0C=273K

Final temperature of the water = T_f  = ?

Change in temperature ,\Delta T=T_f-T_i

Putting in the values, we get:

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2 years ago
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'work' is energy, and  
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So energy is                   (unit of force) x (unit of distance)

                   [Energy]  =       (Newton)            (meter) .

'Newton' itself is a combination of base units, so
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That unit is so complicated that it's been given a special,
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It doesn't matter what kind of energy you're talking about.
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When the person begin to move we have

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Therefore, .

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The answer is C

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