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3 years ago

Teams A and B are in a tug-of-war challenge. Team A wins the challenge. What can be said about Team A?

Physics

2 answers:

Harrizon [31]3 years ago

7 0

Team a was physically stronger?

icang [17]3 years ago

3 0

Answer:

Team A exert more force on ground.

Explanation:

In Tug of war since both teams are pulling two ends of a string or rope so here the net force on the string along with two teams would be zero

So in order to win the game each team has to exert force on the ground.

When team exert more force on the ground then due to the reaction force of ground on the team in opposite direction will help the team to pull the rope towards them

So here if Team A wins the game then the force exerted by that team on the ground must be more due to which the reaction force by ground on the team is of larger magnitude and hence they wins the game

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How does time relate to motion

docker41 [41]

As we move, time goes up. Think of it on a graph; as time increases on the x axis, motion can either stay the same, increase, or decrease.

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2 years ago

What speed would a fly with the mass of 0.55 g need in order to have the same kinetic energy as the automobile in the term 19

larisa86 [58]

The question does not provide enough information to complete the answer, so I'll assume the needed data to help you to solve your own problem

Answer:

The fly should need to move at 9,534.6 m/s to have the same kinetic energy as the automobile

Explanation:

Kinetic Energy

Is the capacity of a body to do work due to its speed and is computed by

$\displaystyle K=\frac{mv^2}{2}$

We are not given enough data to compare the kinetic energy of the fly with that of the automobile. We'll assume the following characteristics:

$m_a=500\ kg$

$v_a=10\ m/s$

So its kinetic energy is

$\displaystyle K_a=\frac{(500)10^2}{2}$

$\displaystyle K_a=25,000\ J$

The mass of the fly is

$m_f=0.55\ gr=0.00055\ kg$

To have the same kinetic as the automobile:

$\displaystyle \frac{m_fv_f^2}{2}=25,000$

Solving for $v_f$

$\displaystyle v_f=\sqrt{\frac{2(25,000))}{m_f}}$

$\displaystyle v_f=\sqrt{\frac{50,000}{0.00055}}$

$v_f=9,534.6\ m/s$

The fly should need to move at 9,534.6 m/s to have the same kinetic energy as the automobile

5 0

3 years ago

The uncertainty Δp sets a lower bound on the average momentum of a particle in the nucleus. If a particle's average momentum wer

kirill [66]

Answer: The minimum kinetic energy Kmin is 1.3 × 10^-13 J

Explanation: Please see the attachments below

8 0

3 years ago

Calculate the wavelength of light that has a frequency of 5.2 x 1012 1/s.

Travka [436]

Answer:

Wavelength = 5.77 * 10^-5 meters.

Explanation:

Given the following data:

Frequency of light = 5.2 *10^12 Hz

We know that the Speed of light = 3.0 * 10^8 m/s

To find the wavelength of light;

Mathematically, wavelength is calculated using this formula;

$Wavelength = \frac {speed}{frequency}$

Substituting into the equation, we have;

$Wavelength = \frac {3*10^{8}}{5.2 *10^{12}}$

Wavelength = 5.77 * 10^-5 meters.

6 0

3 years ago

A 1500-kg car locks its brakes and skids to a stop on a slippery horizontal road, leaving skid marks that are 15 m long. How muc

Harman [31]

Answer:

$E=88200\ J$

Explanation:

Given:

mass of car, $m=1500\ kg$

distance of skidding after the application of brakes, $d=15\ m$

coefficient of kinetic friction, $\mu_k=0.4$

So, the energy dissipated during the skidding of car:

Frictional force:

$f=\mu_k.N$

where N = normal reaction by ground on the car

$f=0.4\ties 1500\times 9.8$

$f=5880\ N$

Now from the work-energy equivalence:

$E=f.d$

$E=5880\times 15$

$E=88200\ J$ is the dissipated energy.

3 0

3 years ago