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3 years ago

Which is a y-intercept of the continuous function in the table?

Mathematics

1 answer:

vitfil [10]3 years ago

8 0

Answer: OPTION 3

Step-by-step explanation:

By definintion, a function intersects the y-axis when the value of "x" is zero ( $x=0$ ).

Then, knowing this, you need to observe the table provided in the exercise and look for the value of $f(x)$ when $x=0$ .

You can notice that when $x=0$ , the value of $f(x)$ is:

$f(x)=5$

Therefore, you can conclude that the function intersects the y-axis at the point $(0,5)$

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2 years ago

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Find the multiplicative inverse of 3 − 2i. Verify that your solution is corect by confirming that the product of

leonid [27]

Answer:

$\frac{3}{13} + \frac{2i}{13}$

Step-by-step explanation:

The multiplicative inverse of a complex number y is the complex number z such that (y)(z) = 1

So for this problem we need to find a number z such that

(3 - 2i) ( z ) = 1

If we take z = $\frac{1}{3-2i}$

We have that

$(3- 2i)\frac{1}{3-2i} = 1$ would be the multiplicative inverse of 3 - 2i

But remember that 2i = √-2 so we can rationalize the denominator of this complex number

$\frac{1}{3-2i } (\frac{3+2i}{3+2i } )=\frac{3+2i}{9-(4i^{2} )} =\frac{3+2i}{9-4(-1)} =\frac{3+2i}{13}$

Thus, the multiplicative inverse would be $\frac{3}{13} + \frac{2i}{13}$

The problem asks us to verify this by multiplying both numbers to see that the answer is 1:

Let's multiplicate this number by 3 - 2i to confirm:

$(3-2i)(\frac{3+2i}{13}) = \frac{9-4i^{2} }{13} =\frac{9-4(-1)}{13}= \frac{9+4}{13} = \frac{13}{13}= 1$

Thus, the number we found is indeed the multiplicative inverse of 3 - 2i

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3 years ago

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3 years ago

What is the cardinality of the set S = {o,r,a,n,g,e}

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Answer:

The cardinality is 6.

Step-by-step explanation:

The cardinality of a set is a measure of the number of elements in the set. The set S has 6 elements, characters as listed, therefore we say the cardinality of the set S is 6, or |S|=6.

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3 years ago