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3 years ago

When heated, KCIO3 decomposes into KCl and O2

Chemistry

1 answer:

Oksana_A [137]3 years ago

5 0

Answer:

Explanation:

First, the KClO3 moles is determined by using given grams of KCl produced from the reaction.

Next, the moles of O2 produced is obtained by using the moles of KClO3 which then, finally converted into mass of O2.

Analyzing the given chemical reaction clearly shows that, 2 moles of KClO3 produces 2 moles of KCl and 3 moles of O2.

From the given grams of KCl produced the initial grams of KClO3 used in the reaction is determined as follows,

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yield = 52.23 %

Explanation:

We have the following chemical reaction:

2 Al (s) + 2 KOH (aq) + 4 H₂SO₄ (aq) + 10 H₂O → 2 KAl(SO₄)₂·12 (H₂O) (s) + 3 H₂ (g)

mass of aluminium = mass of bottle with aluminium pieces - bottle mass

mass of aluminium = 10.8955 - 9.8981 = 0.9974 g

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mass of alum = 19.0414 - 9.8981 = 9.1433 g

number of moles = mass / molecular weight

number of moles of aluminium = 0.9974 / 27 = 0.03694 moles

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To calculate the theoretical quantity of alum that should be obtained from 0.03694 moles of aluminium we devise the following reasoning:

if 2 moles of aluminium produce 2 moles of alum

then 0.03694 moles of aluminium produce X moles of alum

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Learn more about:

reaction yield

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4 years ago