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3 years ago

How much work is done by a 35-watt light bulb if it is on for 1,320 seconds?

Chemistry

1 answer:

OleMash [197]3 years ago

8 0

Answer:

The 35-watt light bulb does a work of 46200 joules in 1320 seconds.

Explanation:

From Physics we remember the definition of work ( $W$ ), measured in joules, by the following integral equation:

$W = \int\limits_{0}^{t} {\dot W} \, dt$ (1)

Where $\dot W$ is the power, measured in watts.

If the power is stable in time, then the work can be calculated by the following algebraic equation:

$W = \dot{W}\cdot \Delta t$ (2)

If we know that $\dot W = 35\,W$ and $\Delta t = 1320\,s$ , then the work done by the 35-light bulb is:

$W = (35\,W)\cdot (1320\,s)$

$W = 46200\,J$

The 35-watt light bulb does a work of 46200 joules in 1320 seconds.

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