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Dmitrij [34]
3 years ago
9

Which group of nuclear emissions is listed in order of increasing charge?

Chemistry
2 answers:
Dmitrij [34]3 years ago
5 0

Answer: Option (4) is the correct answer.

Explanation:

An alpha particle is basically a helium nucleus and it contains 2 protons and 2 neutrons. Symbol of an alpha particle is ^{4}_{2}\alpha or ^{4}_{2}He.

This means that an alpha particle carries a +2 charge.

A positron is a small particle which contains a +1 charge. And, a positron is represent by the symbol ^{0}_{+1}\beta.

A neutron is a sub-atomic particle present inside the nucleus of an atom. Charge on a neutron is 0.

A gamma particle is basically a photon of electromagnetic radiation with a short wavelength.

Symbol of a gamma particle is ^{0}_{0}\gamma. Hence, charge on a gamma particle is also 0.

Therefore, we can conclude that group of nuclear emissions from neutron, positron, alpha particle is listed in order of increasing charge.

shutvik [7]3 years ago
4 0
The nuclear emissions is listed in older of increasing charge are: Neutrons, positron, alpha particles.
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If 16.5g of c6h14o2 are reacted vwith .499 mol of o2. How many moles of co2 should be produced
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Answer:

moles of carbon dioxide produced are 410.9 mol.

Explanation:

Given data:

Mass of C₆H₁₄O₂ = 16.5 g

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First of all we will write the balance chemical equation.

2C₆H₁₄O₂  +  17O₂  →   14CO₂  +  12H₂O

moles of C₆H₁₄O₂  = mass × molar mass

moles of C₆H₁₄O₂ =  16.5 g × 118 g/mol

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Now we compare the moles of CO₂ with moles of O₂ and C₆H₁₄O₂ from balance chemical equation.

                 O₂      :     CO₂

                 17       :      14

                499     :      14/17× 499 = 410.9 moles

          C₆H₁₄O₂   :   CO₂

                    2    :      14

                 1947 :     14/2× 1947 =  13629 moles

Oxygen will be limiting reactant so moles of carbon dioxide produced are 410.9 mol.

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False it can only be one to take place
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