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3 years ago

Which group of nuclear emissions is listed in order of increasing charge?

Chemistry

2 answers:

Dmitrij [34]3 years ago

5 0

Answer: Option (4) is the correct answer.

Explanation:

An alpha particle is basically a helium nucleus and it contains 2 protons and 2 neutrons. Symbol of an alpha particle is $^{4}_{2}\alpha$ or $^{4}_{2}He$ .

This means that an alpha particle carries a +2 charge.

A positron is a small particle which contains a +1 charge. And, a positron is represent by the symbol $^{0}_{+1}\beta$ .

A neutron is a sub-atomic particle present inside the nucleus of an atom. Charge on a neutron is 0.

A gamma particle is basically a photon of electromagnetic radiation with a short wavelength.

Symbol of a gamma particle is $^{0}_{0}\gamma$ . Hence, charge on a gamma particle is also 0.

Therefore, we can conclude that group of nuclear emissions from neutron, positron, alpha particle is listed in order of increasing charge.

shutvik [7]3 years ago

4 0

The nuclear emissions is listed in older of increasing charge are: Neutrons, positron, alpha particles.

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Reacting Solutions of Aluminum Chloride with Potassium Hydroxide

gizmo_the_mogwai [7]

1Al2(SO4)3 + 3ZnCl2 → 2AlCl3 + 3ZnSO4

The coefficients represents moles. There is 1 mole of Aluminum Sulfate, 3 moles of Zinc(II) Chloride, 2 moles of Aluminum Chloride, and 3 moles of Zinc(II) Sulfate.

Now add all the coefficients/moles.

9 is the sum of all the coefficients.

7 0

2 years ago

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139%

GaryK [48]

<u>Answer:</u>

The percent composition of this compound is 94%

<u>Explanation:</u>

The reaction can be formed as

$2 \mathrm{Fe}+3 \mathrm{Cl}_{2} \rightarrow 2 \mathrm{FeCl}_{3}$

$\frac{\text { Weight of } \mathrm{Cl}_{2}}{\text { 3* Molar Mass of } \mathrm{Cl}_{2}}=\frac{\text { Weight of } \mathrm{Fe}}{2 * \text { Molar Mass of Fe }}$

$\frac{\text { Weight of } \mathrm{Cl}_{2}}{3 *(2 * 35.5)}=\frac{3.56}{2 * 55.8}$

$\text { Weight of } C l_{2}=\frac{3.56 * 3 * 71}{2 * 55.8}=6.79 \mathrm{g}$

$\mathrm{n}\left(\mathrm{Cl}_{2}\right)=\mathrm{m}\left(\mathrm{Cl}_{2}\right) / \mathrm{M}\left(\mathrm{Cl}_{2}\right)=6.79 / 71=0.1 \mathrm{m}$

$\mathrm{n}(\mathrm{Fe})=\mathrm{m}(\mathrm{Fe}) / \mathrm{M}(\mathrm{Fe})=3.56 / 55.8=0.06 \mathrm{m}$

Based on no. of iron reacted,

$\mathrm{n}(\text { moles of } \mathrm{Fe})=\mathrm{n}\left(\text { moles of } \mathrm{FeCl}_{3}\right)$

n = m/M

$\mathrm{m}\left(\mathrm{FeCl}_{3}\right)=\mathrm{n}^{*} \mathrm{M}=0.06^{*} 162.5=9.75 \mathrm{g}$

% composition of $FeCl_3$

= $(9.75 / 10.39)^{*} 100$

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6 0

3 years ago

How many formula units are in 239.2g of <br> Br2<br> MgCl2<br> H2O<br> Fe

Oksana_A [137]

The formula units in the substances are as follows:

Br2 = 8.99 × 10^23 formula units
MgCl2 = 1.51 × 10^24 formula units
H2O = 2.57 × 10^24 formula units
Fe = 2.57 × 10^24 formula units

<h3>How many moles are in 239.2 g of the given substances?</h3>

The moles of the substances are determined from their molar mass.

Molar mass of the substances is given as follows:

Br2 = 160 g/mol
MgCl2 = 95 g/mol
H2O = 18 g/mol
Fe = 56 g/mol

Formula units = mass/molar mass × 6.02 × 10^23

The formula units in the substances are as follows:

Br2 = 239.2/160 × 6.02 × 10^23 = 8.99 × 10^23 formula units
MgCl2 = 239.2/95 × 6.02 × 10^23 = 1.51 × 10^24 formula units
H2O = 239.2/18 × 6.02 × 10^23 = 2.57 × 10^24 formula units
Fe = 239.2/56 × 6.02 × 10^23 = 2.57 × 10^24 formula units

In conclusion, the number of formula units is derived from the moles and Avogadro number.

Learn more about formula units at: brainly.com/question/24529075

#SPJ1

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2 years ago

Which half reaction can occur at the anode in a voltaic cell

luda_lava [24]

Oxidation is the half reaction that can occur at the anode in a voltaic cell.

Explanation:

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A half reaction is either the oxidation or reduction reaction component of a redox reaction. A half reaction is obtained by considering the change in oxidation states of individual substances involved in the redox reaction. Half-reactions are often used as a method of balancing redox reactions.

In an oxidation half reaction, an atom loses electron(s). When an element is oxidized it loses a specific number of electrons.

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3 years ago

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Volgvan

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3 years ago

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