What does this look like? Can someone write out the Stoichiometry starting with 50 grams of carbon (use balanced equation)
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Taking into account the Boyle's law, 3.377 L of helium the tank will be able to produce at a pressure of 94.2 kPa.
The gas laws are a set of chemical and physical laws that allow determining the behavior of gases in a closed system. The parameters evaluated in these laws are pressure, volume, temperature, and moles.
Boyle's law is one of the gas laws that relates the volume and pressure of a certain quantity of gas kept at constant temperature.
This law states that the pressure of a gas in a closed container is inversely proportional to the volume of the container, when the temperature is constant. That is, if the pressure increases, the volume decreases; while if the pressure decreases, the volume increases.
Mathematically, Boyle's law states that the product of pressure and volume is constant:
P×V= k
Studying two different states, an initial state 1 and a final state 2, it is satisfied:
P1× V1= P2×V2
In this case, you know:
- P1= 101 kPa
- V1= 3.15 L
- P2= 94.2 kPa
- V2= ?
Replacing in Boyle's law:
101 kPa× 3.15 L= 94.2 kPa× V2
Solving:
<u><em>V2= 3.377 L</em></u>
In summary, 3.377 L of helium the tank will be able to produce at a pressure of 94.2 kPa.
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