The balanced reaction is as follows;
BiCl₂ + Na₂SO₄ --> 2NaCl + BiSO₄
this is a double displacement reaction
the oxidation number of Bi is +2 in both BiCl₂ and BiSO₄
oxidation number of Cl is -1 in both BiCl₂ and NaCl
oxidation number of Na is +1 in both Na₂SO₄ and NaCl
oxidation numbers of elements in SO₄²⁻ remains the same in both compounds.Therefore the oxidation state in any of the elements in the reaction doesn't change. Neither of the elements show an increase or decrease in the oxidation numbers .
Answer for this question is no element decreases its oxidation number.
<h3><u>Answer</u>;</h3>
B. 3/2
<h3><u> Explanation;</u></h3>
Balance the chemical equation
2Al + 3Cl2 → 2AlCl3
We want to convert moles of AlCl3 to moles of Cl2
The conversion factor is 2 mol AlCl3/3 mol Cl2.
We choose the one that makes the units cancel:
x mol AlCl3 x (3 mol Cl3)/(2mol AlCl3) = x mol Al
The fraction for the molar ratio is 3/2.
Anything less that 7, would be a base.