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Nady [450]
3 years ago
6

Which row in the table shows how many electrons there could be in the outer shell of an atom of V? ​

Chemistry
1 answer:
Amanda [17]3 years ago
6 0

Answer:

Explanation:

The element V forms acidic oxide so it must be non- metal because oxides of non metal forms acidic oxide like sulphur ( s ) or chlorine ( Cl₂ )

sulphur forms SO₂ or SO₃ . Chlorine forms acidic oxide like Cl₂O₇ , Cl₂O₃ etc

These oxides are covalent compounds .

So V may have 6 or 7 electrons in the outermost orbit .

Hence option D is the right answer.

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The element carbon exists in several different forms. Pure carbon can be found in the form of diamonds, coal, and the graphite i
bogdanovich [222]

The correct option is B.

Carbon is an element with an atomic number of 6. Each atom of carbon is made up of electron, proton and neutron. Carbon has six protons and six neutrons in its atom but its number of neutrons differ. This is because carbon exhibit isotopy. The isotopes of carbon are: carbon 12, carbon 13 and carbon 14. Carbon 12 has 6 neutrons, carbon 13 has 7 neutrons and carbon 14 has 8 neutrons.

4 0
3 years ago
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The structure of the compound or molecule help predict the name of the compound. Given the binary molecule HCl, which statement
Snezhnost [94]

Answer:

The two nonmetals indicate that covalent naming rules apply.

Explanation:

8 0
4 years ago
The sum of two integers is -4. Can the two integers both be positive?
kaheart [24]

Answer: No.

Explanation: A negative integer can only be made with 2 negative integers or 1 positive and 1 negative integer.

3 0
3 years ago
Use the born-haber cycle to calculate the lattice energy of kcl. (δhsub for potassium is 89.0 kj/mol, ie1 for potassium is 419 k
eduard

Given data:

Sublimation of K

K(s) ↔ K(g)                            ΔH(sub) = 89.0 kj/mol

Ionization energy for K

K(s) → K⁺ + e⁻                         IE(K) = 419 Kj/mol

Electron affinity for Cl

Cl(g) + e⁻ → Cl⁻                      EA(Cl) = -349 kj/mol

Bond energy for Cl₂

1/2Cl₂ (g) → Cl                        Bond energy = 243/2 = 121.5 kj/mol

Formation of KCl

K(s) + 1/2Cl₂(g) → KCl(s)        ΔHf = -436.5 kJ/mol

<u>To determine:</u>

Lattice energy of KCl

K⁺(g) + Cl⁻(g) → KCl (s)                   U(KCl) = ?

<u>Explanation:</u>

The enthalpy of formation of KCl can be expressed in terms of the sum of all the above processes, i.e.

ΔHf(KCl) = U(KCl) + ΔH(sub) + IE(K) + 1/2 BE(Cl₂) + EA(Cl)

therefore:

U(KCl) = ΔHf(KCl) - [ΔH(sub) + IE(K) + 1/2 BE(Cl₂) + EA(Cl)]

         = -436.5 - [89 + 419 + 243/2 -349] = -717 kJ/mol

Ans: the lattice energy of KCl = -717 kj/mol



5 0
3 years ago
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Genrish500 [490]

Answer:

Inference  — The candle stayed lit longer because the plant gave off oxygen.

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Observation — The candle stayed lit longer in closed jar when a plant was present.

Explanation:

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