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LekaFEV [45]
3 years ago
6

Two technicians are discussing headlights. Technician A says that the electricity creates electromagnetic energy in the filament

which illuminates the light. Technician B says that the electricity creates electrochemical energy in the filament which illuminates the light. Who is correct
Physics
1 answer:
Pepsi [2]3 years ago
7 0

Answer:

Technician A only

Explanation:

Here we have electromagnetic energy is an energy form that is emitted from charged objects as electrical and magnetic waves with a capability to move through space as electromagnetic radiation.

Examples of electromagnetic energy and electromagnetic radiation includes, visible light, radio waves, X-rays, gamma rays and Sunlight

While electrochemical energy is the energy through which chemical energy is converted into electrical energy and electrical energy is converted into chemical energy. Electrochemical energy has to do with batteries, super and ultra capacitors and electrochemical cell.

Since the filaments electrical setup does not comprise of an electrochemical cell and light is not a form of chemical energy, therefore, technician A only is correct.

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Weathering, Erosion,  deposition, acid rain, precipitation

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Rahim is watching his favorite football team on television. In order to work, the television must be plugged into an electrical
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Football player A has a mass of 210 pounds and is running at a rate of 5.0mi/hr. He collides with player B. Player B has a mass
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Find the intensity of a 55 dB sound given I 0=10^-12W/m^2
MakcuM [25]

Answer:

3.16 × 10^{-7} W/m^{2}

Explanation:

β(dB)=10 × log_{10}(\frac{I}{I_{0} })

I_{0}=10^{-12} W/m^{2}

β=55 dB

Therefore plugging into the equation the values,

55=10 log_{10}(\frac{I}{ [tex]10^{-12}})[/tex]

5.5= log_{10}(\frac{I}{ [tex]10^{-12}})[/tex]

10^{5.5}= \frac{I}{10^{-12} }

316227.76×10^{-12}= I

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5 0
2 years ago
A girl and a boy are riding on a merry go round that is turning at a constant rate. The girl is near the outer edge, and the boy
galina1969 [7]

Answer:

The girl has greater tangential acceleration

Explanation:

The angular acceleration (\alpha) of the merry go round is equal to the rate of the change of the angular velocity, \omega:

\alpha = \frac{d\omega}{dt}

Since all the points of the merry go round complete 1 circle in the same time, the angular velocity of each point of the merry go round is the same, and so all the points also have the same angular acceleration.

The tangential acceleration instead is given by

a_t = \alpha r

where

\alpha is the angular acceleration

r is the distance from the centre of the merry go round

Since the girl is near the outer edge and the boy is closer to the centre, the value of r for the girl is larger than for the boy, so the girl has greater tangential acceleration.

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3 years ago
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