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dexar [7]
2 years ago
5

An airplane is initially flying horizontally (not gaining or losing altitude), and heading exactly North. Suppose that the earth

's magnetic field at this point is also exactly horizontal, and points from South to North (it really does!). The airplane now starts a different motion. It maintains the same speed, but gains altitude at a constant rate, still heading North. The magnitude of the electric potential difference between the wingtips has... [Remember that the airplane is made of metal, and is a conductor] Group of answer choices
Physics
1 answer:
yanalaym [24]2 years ago
3 0

Note: The answer choices are :

a) Increased

b) Decreased

c) stayed the same

Answer:

The correct option is Increased

The magnitude of the electric field potential difference between the wingtips increases.

Explanation:

The magnitude of the electric potential difference is the induced emf and is given by the equation:

emf = l (v \times B)

where l = length

v = velocity

B = magnetic field

As the altitude of the airplane increases, the magnetic flux becomes stronger, the speed of the airplane becomes perpendicular to the magnetic field, i.e. v \times B = vB sin90 = vB\\ ,

the induced emf = vlB, and thus increases.

The magnitude of the electric field potential difference between the wingtips increases

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Assigned Media Question Help According to a random sample taken at 12​ A.M., body temperatures of healthy adults have a​ bell-sh
deff fn [24]

Answer:

1- \frac{1}{2^2} = 1-\frac{1}{4} = \frac{3}{4}

So then we will have at least 75% of the data within two deviations from the mean \bar x \pm 2s.

\bar x -2s = 98.32 -2*0.59 = 97.14

\bar x +2s = 98.32 +2*0.59 = 99.5

So then the interval would be (97.14, 99.5)

Explanation:

Previous concepts

Chebyshev’s rule is appropriate for any distribution. "Chebyshev’s inequality applies to all distributions, regardless of shape". And is useful since provides a "minimum percentage of the observations that lies within k standard deviations of the mean.  "

If k = 2, at least 3/4 of the measurements lie within 2 standard deviations to within the mean.

And the general formula is (1-1/k^2) represent the fraction of the data within the mean .

Solution to the problem

For this case we want to find the percentage of data that would be at least within two deviations from the mean so for this case the value of k =2 and if we replace we got:

1- \frac{1}{2^2} = 1-\frac{1}{4} = \frac{3}{4}

So then we will have at least 75% of the data within two deviations from the mean \bar x \pm 2s.

For the other part we have the mean and deviation provided \bar x = 98.32 s = 0.59 the interval would be:

\bar x -2s = 98.32 -2*0.59 = 97.14

\bar x +2s = 98.32 +2*0.59 = 99.5

So then the interval would be (97.14, 99.5)

6 0
3 years ago
The plates of a parallel-plate capacitor are oppositely charged and attract each other. Find the expression for the force one pl
Mamont248 [21]

The force exerted by one plate for two parallel plates arrangement is F = QE/2.

<h3>Force one plate exerts on the other</h3>

The force exerted by one plate for two parallel plates arrangement is given as follows;

F = QE/2

where;

  • Q is the charge on one plates
  • E is the electric field due to the charge
  • F is force exerted by one plate

Thus, the force exerted by one plate for two parallel plates arrangement is F = QE/2.

Learn more about force between parallel plates here: brainly.com/question/13590045

5 0
2 years ago
I NEEEED HELPPPPPPP PLEASEEEE
monitta

Answer:

Below

Explanation:

1) To find the average velocity of an object you can use this formula :

     v = ∆displacement / ∆time

     v = 200 m / 5 s

     v = 40 m/s

The average velocity of the turtle is 40 m/s

2) To find the distance an object can travel you can use this formula :

     d = (∆velocity)(∆time)

     d = (20m/s)(5s)

     d = 100 m

The cheetah can run 100 meters in 5 seconds

3) To find the amount of time it takes for an object to move :

     t = ∆displacement / ∆velocity

     t = 5mi / 20 mph

     t = 0.25 h

It would take this car 0.25 h to travel 5 miles at 20 mph

4) To find how far an object can go :

     d = (∆velocity)(∆time)

     d = (20mph)(3h)

     d = 60 mi

The car can drive 60 miles driving 20 mph for 3 hours

5) To find how far an object can go :

     d = (∆velocity)(∆time)

     d = (20mph)(30min)

     d = (20mph)(0.5h)

     d = 10 mi

The car can drive 10 miles driving 20mph for 30 minutes

6) To find how long it would take :

     t = ∆displacement / ∆velocity

     t = 10 m / 50 m/s

     t = 0.2 s

It would take the train 0.2 seconds for a train to travel 10 m at 50 m/s

7) To find how far :

     d = (∆velocity)(∆time)

     d = (670,000,000 mph)(1 yr)

     d = (670,000,000 mph)(8760 h)

     d = 5869200000000 mi

1 light year is 5869200000000 miles

Hope this helps! Best of luck <3

6 0
3 years ago
Two points are located on a rigid wheel that is rotating with decreasing angular velocity about a fixed axis. Point A is located
Nata [24]

Answer:

4. Both points have the same instantaneous angular velocity

Explanation:

Angular velocity is a measure of the the number of rotations per unit time. This does not depend on the radius of the wheel. Hence, all points on the wheel have the same angular velocity. This invalidates option 1.

The centripetal acceleration is given by the product to the square of the angular velocity and the radius or distance from the centre. A and B are located at different distances from the centre. Hence, they have different centripetal acceleration. This invalidates option 2.

The tangential acceleration depends on the linear velocity which itself is a product of the angular velocity and the distance from the centre. Hence, it is different for both points because they are at different distances from the centre.

Since both A and B are fixed points on the wheel, they move through equal angles in the same time. In fact, for any other fixed point, they all move through the same angle in the same time. This invalidates option 5.

4 0
2 years ago
Along some shorelines, incoming waves cause the water to simply rise and fall rather that form a surf zone. What does this tell
NARA [144]

Answer:

Explained

Explanation:

Along some shorelines, incoming waves cause the water to simply rise and fall and not form surfs because of the steepness of the shorelines. Long period waves wont form surfs at steep shores because of the breaking and unstability of waves. Wave breaks at the shallow waters. The breaking of the waves depends upon H/L ratio.

5 0
2 years ago
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