To find the zeros of this equation you need to first set it equal to zero
2x2 + 16x - 9 = 0
But since you can't FOIL this equation you need to move the non-variable number over
2x2 +16x = 9
Now solve for x by pulling an x out of the equation
x(2x + 16) = 9
x = 9
2x +16 = 9
2x = -7
x = -7/2
So your zeros would be at x = 9, and -7/2
Answer:
3 quarters and 1 dime
Step-by-step explanation:
Pretty simple. 0.85 = 0.75 + 0.1, so you can make it into a dime plus 0.75. 0.75 is 3 * 0.25, so it is 3 quarters. Therefore, the answer is 3 quarters and 1 dime.
This process is:
<span>Distribute of the Negative Sign:
</span><span><span><span>5t</span>+t</span>−3</span>+<span><span>−1</span><span>(<span><span><span>7t</span>+5</span>−<span>(<span>8−<span>3t</span></span>)</span></span><span>)
</span></span></span><span><span><span><span><span><span><span>5t</span>+t</span>+</span>−3</span>+<span><span>−1</span><span>(<span>7t</span>)</span></span></span>+<span><span>(<span>−1</span>)</span><span>(5)</span></span></span>+<span><span>(<span>−1</span>)</span><span>(<span>−8</span>)</span></span></span>+<span><span>−1</span><span>(<span>3t</span>)</span></span>
<span><span><span><span><span><span><span><span><span><span>5t</span>+t</span>+</span>−3</span>+</span>−<span>7t</span></span>+</span>−5</span>+8</span>+</span>−<span>3<span>t
</span></span>Now simple, Just Combine Like Terms:
<span><span><span><span><span><span><span>5t</span>+t</span>+<span>−3</span></span>+<span>−<span>7t</span></span></span>+<span>−5</span></span>+8</span>+<span>−<span>3<span>t
</span></span></span></span><span>(<span><span><span><span>5t</span>+t</span>+<span>−<span>7t</span></span></span>+<span>−<span>3t</span></span></span>)</span>+<span>(<span><span><span>−3</span>+<span>−5</span></span>+8</span><span>)
</span></span>−<span>4<span>t
</span></span>
-4t would be the answer.
~Evie
The downward and upward distances form two geometric sequences.
The sum of downward distance is:
s(n)=16(1-.5^n)/(1-.5)
The sum of upward distance is:
s(n)=8(1-.5^(n-1))/(1-.5)
If we let these sums be d(n) and u(n) for upward and downward distances, and neaten them up a bit we have:
d(n)=32(1-.5^n) and u(n)=16(1-.5^(n-1))
So the total vertical distance traveled when the ball hits the ground for the seventh time is:
D=32(1-.5^7)+16(1-.5^6)
D=32(0.9921875)+16(0.984375)
D=31.75+15.75
D=47.5 ft