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dlinn [17]
3 years ago
15

At a restaurant, Trevor decides to tip the server 16% of the bill. If he leaves a $4.00 tip, which proportion could be used to f

ind how much the bill was for?
Mathematics
2 answers:
PolarNik [594]3 years ago
7 0

Answer:

16% of x = 4  or  0.16x = 4

Step-by-step explanation:

Let the amount of the restaurant bill is $x.

Now we know Trevor leaves 16% of the bill as a tip

Therefore, amount of tip will be 16% of x

this amount is $4.

So equation for this situation will be

16% of x = 4  or  0.16x = 4

Andreyy893 years ago
3 0
16% of 25$ (the bill) is 4$
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A regular polygon
olga55 [171]

Answer:

3.6° = ext. angle

Step-by-step explanation:

For the shape to be a regular polygon, all interior angles must be congruent.

We can find every interior angle by using the formula:

\frac{180(n-2)}{n}

\frac{180(100-2)}{100}

\frac{180(98)}{100}

\frac{17640}{100}

176.4 = each int. angle

We also know that int. and ext. angles are supplementary!

180 = 176.4 - x

3.6° = ext. angle

5 0
3 years ago
Milo is a show dog. Her trainer wants her to have a beautiful and brilliant coat.
icang [17]

Answer:

did she like it?

Step-by-step explanation:

3 0
3 years ago
Solve the system of equations using elimination. How many solutions does the system have?
Morgarella [4.7K]

Answer:

I hope it helps u

Step-by-step explanation:

Let's solve your system by elimination.

15j+12k=18;5j+4k=6

Multiply the second equation by -3, then add the equations together.

(15j+12k=18)

−3(5j+4k=6)

Becomes:

15j+12k=18

−15j−12k=−18

Add these equations to eliminate j:

0=0

Answer:

Infinitely many solutions

Note:  Please Brain-list it ok dear!

If u have any doubt you can ask ok

6 0
2 years ago
Two particles are fixed to an x axis: particle 1 of charge -1.00 x 10-7 C is at the origin and particle 2 of charge +1.00 x 10-7
r-ruslan [8.4K]
The electric field strength at any point from a charged particle is given by E = kq/r^2 and we can use this to calculate the field strength of the two fields individually at the midpoint. 

The field strength at midway (r = 0.171/2 = 0.0885 m) for particle 1 is E = (8.99x10^9)(-1* 10^-7)/(0.0885)^2 = -7.041 N/C and the field strength at midway for particle 2 is E = (8.99x10^9)(5.98* 10^-7)/(0.0935)^2 = <span>-7.041 N/C
</span>
Note the sign of the field for particle 1 is negative so this is attractive for a test charge whereas for particle 2 it is positive therefore their equal magnitudes will add to give the magnitude of the net field, 2*<span>7.041 N/C </span>= 14.082 N/C
6 0
3 years ago
If 6x+7°and 8x-17°are vertical angles, whats x
kolezko [41]
Since the two measures are vertical angles, you want to set them equal to each other :

6x+7=8x-17
-6x -6x
——————
7=2x-17
+17 +17
———————
24= 2x
X= 12
———

The answer is 12.
4 0
3 years ago
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