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2 years ago

An agent buys an item at 70% of its value and sells it at 10% more than its value. What percent of the cost is his profit?

1 answer:

8 0

Lets say the initial cost is 100 dollars. The agent would buy it for 70 dollars. If he sold it for 10% more than what he bought it for, he would be selling it for 77 dollars, making a total profit of 37 dollars. This would mean that he made a 48% profit.

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Martina purchased a prepaid phone card for $20. long distance calls cost 13 cents a minute using this card. Martina used her car

Dima020 [189]

Phone card = $20
You need to minus 17.92 from 20 = $2.08
$2.08 / 0.13 = how many minutes
= 16

7 0

3 years ago

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SOMEONE PLEASE HELP ME ASAP PLEASE!!!

KiRa [710]

Answer:

(0,3)

Step-by-step explanation:

(-4+4)/2=0

(7+(-1))/2 = 3

4 0

2 years ago

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The bases of the trapezoid are 6 and 10. The height is 4. Find the area. 30 sq. units 32 sq. units 64 sq. units

pychu [463]

Answer: The answer is: [B]:

__________________________________________________

→ " 32 sq. units " .

__________________________________________________

→ The area of the trapezoid is: " 32 sq. units " .

__________________________________________________

Step-by-step explanation:

__________________________________________________

The formula for the Area, "A" ; of a "trapezoid" is:

A = ½ * (b₁ + b₂) * h ;

_________________________________________________

in which:

" A " ; is the "area" (for which we shall solve) ;

" b₁ " ; is the "base length" (of "one of the bases") of the trapezoid;

" b₂ " ; is the "base length" (of the "other" base) of the trapezoid ;

" h " ; is the "height" [perpendicular height] of the trapezoid ;

_________________________________________________

Now, let us plug in our "given values" into the equation/formula ;

and calculate; to solve for the: area; "A" ; of the "trapezoid" ;

in "sq. units" ;

_________________________________________________

Given:

" b₁ = 6 " ;

" b₂ = 10 " ;

" h = 4 " ;

_________________________________________________

→ A = ½ * (b₁ + b₂) * h ;

→ = ½ * (6 + 10) * 4 ;

→ = ½ * (16) * 4 ;

→ = 8 * 4 ;

→ A = 32 sq. units ;

________________________________________________

→ The area of the trapezoid is: " 32 sq. units ";

→ which is: Answer choice: [B]: " 32 sq. units " .

_________________________________________________

Hope this is helpful to you!

Best wishes to you in your academic pursuits

— and within the "Brainly" community!

_________________________________________________

6 0

2 years ago

A scuba diver descends from the surface at a rate of 38 feet per minute

Bezzdna [24]

38+38+38=114 Hoped this helped

3 0

1 year ago

NEED HELP ASAPPPPPPPPP

Nookie1986 [14]

Answer:

A = 57°

B = 19°

C = 104°

Step-by-step explanation:

We have a triangle with 3 angles:

A, B, and C.

We know that:

"Angle A is 3 times larger than angle B"

We can write this as:

A = 3*B

"Angle C was 10° less than 6 times angle B"

This can be written as:

C = 6*B - 10°

And we also know that the sum of all interior angles of a triangle is 180°

Then we also have the equation:

A + B + C = 180°

So we have a system of 3 equations:

A = 3*B

C = 6*B - 10°

A + B + C = 180°

To solve this, the first step is to isolate one of the variables in one of the equations.

We can see that A is already isolated in the first one, so we can skip that step.

Now we need to replace A in the other equations, to get:

C = 6*B - 10°

(3*B) + B + C = 180°

Now we have a system of two equations.

Let's do the same procedure, we can see that C is isolated in the top equation, so we can just replace that in the other equation to get:

3*B + B + (6*B - 10°) = 180°

Now we can solve this for angle B

4*B + 6*B - 10° = 180°

10*B - 10° = 180°

10*B = 180° + 10° = 190°

B = 190°/10 = 19°

Now that we know the measure of angle B, we can input this in the equations:

A = 3*B

C = 6*B - 10°

To find the measures of the other two angles:

A = 3*19° = 57°

C = 6*19° - 10° = 104°

5 0

2 years ago