According to the fact that t<span>hey both include the reaction change of elements through different processes, there should be a nice connection between them. In math, numbers pose as an element, and in chem - </span><span>elements are physical things. Both of them can change due to reaction or a formula.</span>
Answer:
See Explanation
Explanation:
Let us recall that;
[H^+] [OH^-] = 1 * 10^-14
Where;
[OH^-] = 1 x 10^-11
Then;
[H^+] = 1 * 10^-14/1 x 10^-11
[H^+] = 1 * 10^-3
pH = -log [H^+]
pH = -log(1 * 10^-3)
pH = 3
Also;
pH + pOH = 14
pOH = 14 - pH
pOH = 14 -3
pOH = 11
<u>Answer:</u> The pressure of NO and 
in the mixture is 0.58 atm and 0.024 atm respectively.
<u>Explanation:</u>
We are given:
Equilibrium partial pressure of 
= 0.29 atm
For the given chemical equation:
Initial: a
At eqllm: a-2x 2x x
Calculating for the value of 'x'
Equilibrium partial pressure of NO = 2x = 2(0.29) = 0.58 atm
Equilibrium partial pressure of = a - 2x = a - 2(0.29) = a - 0.58
The expression of 
for above equation follows:
We are given:
Putting values in above expression, we get:
Neglecting the value of a = 0.555 because it cannot be less than the equilibrium concentration.
So, 
Equilibrium partial pressure of = (a - 0.58) = (0.604 - 0.58) = 0.024 atm
Hence, the pressure of NO and in the mixture is 0.58 atm and 0.024 atm respectively.
When the volume and quantity of the gas are held constant, we can use the Gay-Lussac's Gas Law expressed as
P1/T1 = P2/T2
in which if the pressure of the gas decreases, we know that the temperature decreases.
We first convert the temperature to absolute temperature
T1 = 70 + 273 = 343 K
Rearranging the Gay-Lussac's equation to solve for the final temperature
T2 = P2T1 / P1
= (720 mmHg)(343 K) / 740 mmHg
= 334 K = 61ºC
If you mix salt sand and sugar with water what will the mixture be a solution because both sugar and salt can be diluted until the saturation point
