Answer:
7.08
Explanation:
To solve this problem we'll use the <em>Henderson-Hasselbach equation</em>:
- pH = pka + log
![\frac{[A^-]}{[HA]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BA%5E-%5D%7D%7B%5BHA%5D%7D)
Where is the ratio of [sodium formate]/[formic acid] and pka is equal to -log(Ka), meaning that:
- pka = -log (1.8x10⁻⁴) = 3.74
We<u> input the data</u>:
- 4.59 = 3.74 + log
And<u> solve for </u>:
- 0.85 = log
=
- = 7.08
Answer:
V = 14.2 L
Explanation:
Given data:
Moles of CO₂ = 0.632 mol
Temperature = standard = 273 K
Pressure = standard = 1 atm
Volume of gas = ?
Solution;
Formula:
PV = nRT
R = general gas constant = 0.0821 atm.L/ mol.K
Now we will put the values in formula.
V = nRT/P
V = 0.632 mol ×0.0821 atm.L/ mol.K × 273 K / 1 atm
V = 14.2 L/ 1
V = 14.2 L
Energy cannot be destroyed or created. Electricity is a form of energy which has to be created from other forms of energy. We have to pay for the creation of electricity because it requires certain resources to transform other energies into electricity.
Fluorine has C seven valence electrons.
Valence electrons are the electrons that are found on the outer shell of an atom that are capable of participating in chemical reactions. The easiest way to figure out how many valance electrons Fluorine has would be to look it up in a periodic table and notice that it a group 7 element and therefore has 7 valence electrons.
The other way to tell that Fluorine has 7 valence electrons is to notice that an element with an atomic number of 9 has 9 electrons. The electronic configuration of elements has the first 2 electrons go on the first shell or energy level 
, the leaving the next 7 to go to the second shell 
which can take up to 8 electrons.
This means that Fluorine has 7 seven valence electrons.
What are the following answers?
