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lina2011 [118]
3 years ago
9

If sulfur dioxide and oxygen can be made into sulfur trioxide, what is the reverse reaction? A. SO3 +O2à SO3 B. 2SO2 + O2à 2SO3

C. 2SO3à2SO2+O2. D. SO2+2SO3à 3S +4O2
Chemistry
2 answers:
ycow [4]3 years ago
7 0
REVERSE REACTION WILL BE SO2+O2
solong [7]3 years ago
3 0

<u>Answer: </u>The correct answer is Option C.

<u>Explanation:</u>

Reverse reaction is defined as the chemical reaction in which the reactants forming products at first, react together to give back the reactants.

Forward reaction is given by the equation:

A+B\rightarrow C+D

Now, the reverse reaction for this will be:

C+D\rightarrow A+B

  • According to the question:

Sulfur dioxide and oxygen are reacting together to form sulfur trioxide. The forward reaction for this will be:

2SO_2+O_2\rightarrow 2SO_3

The reverse reaction for this will be:

2SO_2\rightarrow 2SO_2+O_2

Hence, the correct answer is Option C.

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Which statement is correct about the reaction that occurs between calcium chloride and sodium carbonate? It is a single replacem
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Answer: It is a double replacement reaction because calcium chloride and sodium carbonate exchange their non-metallic parts.

Explanation:

Double displacement reaction:  It is a type of chemical reaction in which two reactants exchange their ions to form new compound as a product. In this type of reaction product is obtained in the form of a precipitate.

AB+CD\rightarrow AD+CB

CaCl_2+Na_2CO_3\rightarrow CaCO3+2NaCl

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1. Household bleach (NaOCl) is really a solution of sodium hypochlorite in water. It is made by reacting chlorine gas and sodium
Sergio039 [100]

This is a three-part question

Answers:

  • a) The oxidation number of chlorine in bleach (NaOCl) is +1.

  • b) Yes, this is a redox reaction

  • c) The percen yield is 56.8%

Explanation:

<u>1) Part (a) What is the oxidation number of chlorine in bleach (NaOCl)? </u>

a) <u>Rule one</u>: In a neutral compound the sum of the oxidation states is zero.

Since NaOCl is a neutral compound the sum of the oxidation states of Na, O and Cl is 0.

b) <u>Rule two</u>: since Na is an alkaline metal, its oxidation state is +1

c) <u>Rule three</u>: the most common state of oxygen, except in peroxides, is -2.

Then,

  • Na: +1
  • O:   -2
  • Cl:    x

      Sum = +1 - 2 + x = 0 ⇒ x = 2 - 1 = 1

<u>Conclusion</u>: the oxidation state of NaOCl is +1.

<u>2) Part (b) Is this reaction above redox?  </u>

In a redox reaction the oxidation states of some substances increase (get oxidized) and the oxidation states of some substances decrease (get reduced).

The reaction is represented by the chemical equation given:

  • NaOH (aq) + Cl₂ (g) → NaOCl (aq) + NaCl (aq) + H₂O (l)

Since the chlorine gas (Cl₂) is a molecule of only chlorine atoms, its oxidation state is zero, and since chlorine is forming compounds on the right side (NaOCl and NaCl) you can immediately conclude that the oxidation state of chlorine changed, and this is a redox reaction.

In fact:

  • Oxidation state of Cl in Cl₂: 0
  • Oxidation state of Cl in NaOCl: +1 (previously determined)
  • Oxidation state of Cl in NaCl: -1 (becasue Na has oxidation state +1 and so +1 - 1 = 0).

Therefore, chlorine is being oxidized (its oxidation state increases from 0 to +1) and is also being reduced (its oxidation state is reduced from 0 to -1), and this is a redox reaction.

<u>3) Part (c) What is the percent yield of this reaction?</u>

a) <u>Chemical equation (given)</u>

  • NaOH (aq) + Cl₂ (g) → NaOCl (aq) + NaCl (aq) + H₂O (l)

b) <u>Theoretical mole ratio:</u>

  • 2 mol Cl₂ (g) : 1 mol  NaOCl (aq)

c)  <u>Convert 83.0 g of chlorine gas to moles:</u>

  • moles = mass in grams / molar mass
  • molar mass of Cl₂(g) = 79.906 g/mol
  • moles = 83.0 g / 79.906 g/mol = 1.039 mol Cl₂(g)

d)<u> Determine the theoretical yiedl using proportions</u>:

  • x / 1.039 mol Cl₂ (g) = 1 mol NaOCl / 2 mol Cl₂ (g)

  • ⇒ x = 0.5195 mol NaOCl

e) <u>Convert 0.5195 mol NaOCl to grams:</u>

  • molar mass NaOCl = 22.99 g/mol + 16.00 g/mol + 35.453 g/mol = 74.443 g/mol

  • mass = number of mol × molar mass = 0.5195 mol × 74.443 g/mol = 38.67 g

         That must be rounded to 3 significant figures (such as the mass of belach is given: 22.0 g)

  • Theoretical yiedl of NaOCl = 38.7 g

f) <u>Calculate the percent yiled</u>:

  • Percent yield = (actual yield / theoretical yield) × 100
  • Percent yield = (22.0 g / 38.7 g) × 100 = 56.8%

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There are two problems for this question:1. What is the total dollar amount of your profit and loss:
Put option premium is equal to 0.04 per unit.
The exercise price is 1.22
One option contract is 100,000
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Net profit is = 0.02 x 100,000 = 2,000 – 80 = 1,920

2. Now undertake that as an alternative of taking a position in the put option one year ago, you sold a future's contract on 100,000 euros with a payment date of one year.
Find the total dollar amount of your profit or loss.
Solution: Contract to buy: $1.20 x 100,000 = 120,000 at payment date.
Contract to sell: $1.22 x 100,000 = 122,000 at settlement date
Settle contracts: -2,000 - 80 = -$2,080
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