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Nadya [2.5K]
3 years ago
10

Draw the most stable resonance structure for the intermediate in the electrophilic aromatic bromination of aniline, anisole, and

acetanilide to make the respective monobrominated products. compare their relative stability and the predict the relative reactivities of each starting compound.

Chemistry
1 answer:
ASHA 777 [7]3 years ago
4 0

Answer:

Here's what I get

Explanation:

(a) Intermediates

The three structures below represent one contributor to the resonance-stabilized intermediate, in which the lone pair electrons on the heteroatom are participating (the + charge on the heteroatoms do not show up very well).

(b) Relative Stabilities

The relative stabilities decrease in the order shown.

N is more basic than O, so NH₂ is the best electron donating group (EDG) and will best stabilize the positive charge in the ring. However, the lone pair electrons on the N in acetanilide are also involved in resonance with the carbonyl group, so they are not as available for stabilization of the ring.

(c) Relative reactivities

The relative reactivities would be

C₆H₅-NH₂ >  C₆H₅-OCH₃ > C₆H₅-NHCOCH₃

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The periodic table is useful because it is organized to show many patterns and trends. What property shows a decrease moving fro
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Atomic radius

Explanation:

A decrease in moving from the bottom of Group 3 to the top of the group shows an increase in trend from top to bottom.

The atomic radius of elements increases from top to bottom and decreases from the bottom to the top.

The elements in group 3 are B, Al , Ga, In and Tl

  • Atomic radius is taken as half of the inter-nuclear distance between two covalently bonded atoms of non-metallic elements or half of the distance between two nuclei in the solid state of metals.
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3 0
3 years ago
You have 54.32 grams of PbCl4. How many moles of PbCl4 do you have?
Dima020 [189]

Answer:

0.156mol

Explanation:

Number of moles of a substance can be calculated from its mass by dividing its mass by molar mass i.e.

Number of moles (n) = mass/molar mass

Molar mass of PbCl4 is as follows, where Pb = 207.2g/mol, Cl = 35.5g/lol

PbCl4 = 207.2 + 35.5(4)

= 207.2 + 142

= 349.2g/mol

Using: mole = mass/molar mass

mole = 54.32 grams ÷ 349.2g/mol

mole = 0.1555

mole = 0.156mol

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