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Nadya [2.5K]
3 years ago
10

Draw the most stable resonance structure for the intermediate in the electrophilic aromatic bromination of aniline, anisole, and

acetanilide to make the respective monobrominated products. compare their relative stability and the predict the relative reactivities of each starting compound.

Chemistry
1 answer:
ASHA 777 [7]3 years ago
4 0

Answer:

Here's what I get

Explanation:

(a) Intermediates

The three structures below represent one contributor to the resonance-stabilized intermediate, in which the lone pair electrons on the heteroatom are participating (the + charge on the heteroatoms do not show up very well).

(b) Relative Stabilities

The relative stabilities decrease in the order shown.

N is more basic than O, so NH₂ is the best electron donating group (EDG) and will best stabilize the positive charge in the ring. However, the lone pair electrons on the N in acetanilide are also involved in resonance with the carbonyl group, so they are not as available for stabilization of the ring.

(c) Relative reactivities

The relative reactivities would be

C₆H₅-NH₂ >  C₆H₅-OCH₃ > C₆H₅-NHCOCH₃

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Answer: 8.59 L of oxygen gas are needed to produce 100 kJ of energy at STP

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

Standard condition of temperature (STP)  is 273 K and atmospheric pressure is 1 atmosphere respectively.  

1 mole of every gas occupy volume at STP = 22.4 L

The balanced chemical reaction is:

2C_6H_6(I)+15O_2(g)\rightarrow 12CO_2(g)+6H_2O(g)

3909.9 kJ of of energy is produced by  = 15\times 22.4=336L

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The compound that contains a radical is called NaOH.

Explanation:

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Answer:

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Explanation:

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