The lighter one travel with the speed of 0.574 m/sec. Force is defined as the product of mass and acceleration. Its unit is Newton.
<h3>What is force?</h3>
Force is defined as the push or pull applied to the body. Sometimes it is used to change the shape, size, and direction of the body.
The two skaters push off against each other on frictionless ice, then torque act by the one skater on the other is equal.
P₁₂=P₂₁
F₁₂V₁ =F₂₁V₂
625 ×V₁= 725 N× 1.5 m/s
V₁=0.574 m/sec
Hence, the lighter one travel with the speed of 0.574 m/sec.
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Answer:
P=1.53 i +1.92 j kg.m/s
P=2.45 kg.m/s
α = 51.34
Explanation:
Given that
m=123 g = 0.123 Kg
U= 25 m/s
θ=30°
t= 0.6 s
This is the case of projectile motion
So the horizontal component of velocity U = u cosθ
u = 25 cosθ
u = 25 cos 30°
u=21.65 m/s
The vertical component of velocity U = U sinθ
Vo= U sinθ
Vo= 25 sin 30°
Vo = 12.5 m/s
We know that horizontal component of velocity of ball will remain same.So the horizontal component of momentum
Px= m u
Px= 0.143 x 12.5 kg.m/s
Px=1.53 kg.m/s
The vertical component of ball after 0.6 s
V= Vo- g t
V= 21.65 - 10 x 0.6 m/s
V= 15.65 m/s
Py= m V
Py= 0.123 x 15.65 kg.m/s
Py=1.92 kg.m/s
P=1.53 i +1.92 j kg.m/s
Magnitude P
P=2.45 kg.m/s
Direction
α = 51.34° (measured from x direction)
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Answer:
force for start moving is 7.49 N
force for moving constant velocity 2.25 N
Explanation:
given data
mass = 7.65 kg
kinetic coefficient of friction = 0.030
static coefficient of friction = 0.10
solution
we get here first weight of block of ice that is
weight of block of ice = mass × g
weight of block of ice = 7.65 × 9.8 = 74.97 N
so here Ff = Fa
so for force for start moving is
Fa = weight × static coefficient of friction
Fa = 74.97 × 0.10
Fa = 7.49 N
and
force for moving constant velocity is
Fa = weight × kinetic coefficient of friction
Fa = 74.97 × 0.030
Fa = 2.25 N
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