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Anton [14]
4 years ago
12

cooling down after a workout allows the oxygen to continuing moving through the body and keeps the muscles from tightening up to

fast
Physics
2 answers:
Fynjy0 [20]4 years ago
6 0
<span>This gives your muscles a chance to relax and prevents your blood pressure from dropping too rapidly, which can happen if your blood is allowed to pool in your extremities.</span>
Anvisha [2.4K]4 years ago
4 0
I think the answer is true
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Because weight is a measurement of the amount of gravity pulling on an object, weight is considered a ______. Question 18 option
Andrews [41]

Answer: Force I believe.

6 0
2 years ago
A sound source of frequency f moves with constant velocity (less than the speed of sound) through a medium that is at rest. A st
ANTONII [103]

Answer:

The correct answer is d

Explanation:

In this exercise they ask us which statement is correct, for this we plan the solution of the problem, this is a Doppler effect problem, it is the frequency change due to the relative speed between the emitter and the receiver of sound.

The expression for the Doppler effect of a moving source is  

f ’= (v / (v- + v_s) f  

From this expression we see that if the speed the sound source is different from zero feels a change in the  frequency.

The correct answer is d

7 0
3 years ago
NEED HELP ASAP PLEASE
Zarrin [17]

Answer:

D. 3.0 m/s

Explanation:

because I did this in my class

8 0
3 years ago
A single-turn circular loop of wire of radius 5.0 cm lies in a plane perpendicular to a spatially uniform magnetic field. During
Artemon [7]

Answer:

Induced EMF,\epsilon=0.0143\ volts

Explanation:

Given that,

Radius of the circular loop, r = 5 cm = 0.05 m

Time, t = 0.0548 s

Initial magnetic field, B_i=200\ mT=0.2\ T

Final magnetic field, B_f=300\ mT=0.3\ T

The expression for the induced emf is given by :

\epsilon=\dfrac{d\phi}{dt}

\phi = magnetic flux

\epsilon=\dfrac{d(BA)}{dt}

\epsilon=A\dfrac{d(B)}{dt}

\epsilon=A\dfrac{B_f-B_i}{t}

\epsilon=\pi (0.05)^2\times \dfrac{0.3-0.2}{0.0548}

\epsilon=0.0143\ volts

So, the induced emf in the loop is 0.0143 volts. Hence, this is the required solution.

5 0
3 years ago
A vertical spring stretches 4.0 cm when a 12-g object is hung from it. The object is replaced with a block of mass 28 g that osc
marin [14]

Answer:

Time period of the osculation will be 0.0671 sec  

Explanation:

It is given a vertical spring is stretched by 4 cm

So change in length of the spring x = 4 cm = 0.04 m

Mass which is hung from it m = 12 gram = 0.012 kg

Sprig force will be equal to weight of the mass

So kx=mg

k\times 0.04=0.012\times 9.8

k = 244.7 N/m

Now new mass is m = 28 gram = 0.028 kg

So time period with new mass will be

T=2\pi \sqrt{\frac{m}{k}}

=2\times 3.14 \sqrt{\frac{0.028}{244.7}}=0.0671sec

4 0
3 years ago
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