Answer:
1) A = 0.25 m², 2) V = 0.5 m³, 3) m = 1500 kg, 4) W = 14700 N,
5) P = 58800 Pa
Explanation:
1) The area of the base is square
A = L²
A = 0.5²
A = 0.25 m²
2) The block is a parallelepiped
V = A h
V = 0.25 2
V = 0.5 m³
3) Density is defined
rho = m / V
m = rho V
m = 3000 0.5
m = 1500 kg
4) The weight of a body is
W = mg
W = 1500 9.8
W = 14700 N
5) The pressure is
P = F / A
in this case the force is equal to the weight of the body
P = 14700 / 0.25
P = 58800 Pa
Answer:
f = 15 N
Explanation:
It is given that, when you push with a horizontal 15-N force on a book that slides at constant velocity, a frictional force also acts on it. Frictional force is an opposing force. The magnitude of applied force and frictional forces are same. So, the force of friction on the book is equal to 15 N.
Mass is a measure of the amount of matter in a substance or an object.
The charge on the droplet must be
Explanation:
In order for the oil droplet to be in equilibrium, the force of gravity acting on it (the weight, acting downward) must be equal to the electrical force acting upward.
The gravitational force is:
which is equivalent to the weight of the droplet.
The electric force is given by:
where
q is the charge on the oil droplet
is the magnitude of the electric field
Since the two forces must be equal,
And solving for q,
Learn more about gravitational force and electric force:
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In the absence of a diagram the general answer to the roller coaster scenario is as follows. Energy is always conserved in nature and if we exclude the energy losses due to friction in the moving parts and surfaces of the roller coaster, the sum of kinetic and potential energy of the car will always equate to the same number, called the mechanical energy.
As the rollercoaster moves you can imagine energy flowing between kinetic and potential states. The highest potential energy will be the highest and slowest point on the track, this will also be the lowest kinetic energy state. Similarly, the highest kinetic energy will be the lowest and fastest point on the course, which is also the point of lowest potential energy.