Set x as adult tickets.
Set y as children's tickets.
x + y = 15
30x + 20y = 270
Solve for x in the first equation.
x + y = 15
x = 15 - y
Plug this into the second equation.
30x + 20y = 270
30(15 - y) + 20y = 270
450 - 30y + 20y = 270
450 - 10y = 270
-10y = -180
y = 18
If there is 18 childrens tickets, there should be -3 adult tickets.
This is impossible, and this impossible answer occured because the question is written wrong.
There are a total of 15 tickets
The smallest costing ticket is the childrens ticket, which costs 20$.
If he only bought children tickets, this would be 20x15 which is 300$.
300$ is over 270$, which makes the question impossible.
Answer: -2/3
Step-by-step explanation:
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Answer:
Step-by-step explanation:
I don't do this question the same way as it is done in the classroom, but I will get you the right answer
Let the middle number = x
Let the smallest number = x - 2
Let the largest number = x + 2
x - 2 + x + x + 2 = 315 Combine like terms. The 2s cancel
3x = 315 Divide by 3
x = 105
So the middle number is 105
The smallest number is 103
The largest number is<u> 107</u>
Total 315
This method cuts out at least one step. It works best with an odd number of terms. If you have an even number, you have to use the more traditional method.
