Let cheese wafers = x
chocolate wafers = y
we know they bought 20 total packets so x+y = 20, this can be re-written as x = 20-y
cheese wafers cost 2, so we have 2x
chocolate wafers cost 1, so we have 1y, which is just the letter y
so we know 2x + y = $25
replace x with x=20-y to get:
2(20-y)+y = 25
distribute the parenthesis:
40-2y +y = 25
combine like to terms to get:
40-y = 25
subtract 40 from each side"
-y = -15
divide both sides by -1
y = 15
chocolate wafers was y so they bought 15 chocolate wafers
cheese wafers was x, so they bought 20-15 = 5 cheese wafers
using the substitution method was the easiest way to isolate one of the variables in order to find the solution.
Answer:
-4
Step-by-step explanation:
1. 6v-10=2v-22-4
2. 4v-10=-26
3. 4v=-16
4. v=-4
Answer:
32
Step-by-step explanation:
The number that take algebra i includes those who take both subjects, as does the number taking algebra ii. Then the number taking algebra i alone is ...
18 -10 = 8 . . . . . take only algebra i
So the number taking any kind of algebra is ...
20 + 8 = 28
and the number not taking either subject is ...
60 -28 = 32 . . . not taking either subject
