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andriy [413]
3 years ago
13

Suppose you are the manager of a watchmaking firm operating in a competitive market. Your cost of production is given by C = 200

+ 2q^2, where q is the level of output and C is total cost. (The marginal cost of production, MC(q), is 4q; the fixed cost, FC, is $200). a. If the price of a watch is $80, how many watches should you produce to maximize profits? (Enter your response as an integer.) b. What will the profit level be? (Enter your response rounded to two decimal places.) c. At what minimum price will the firm produce a positive output? (Enter your response as an integer.)
Business
1 answer:
irga5000 [103]3 years ago
4 0

Answer:

1. 20 units

2. $600

Explanation:

1. C = 200 + 2q^{2}

MC = 4q

Price, P = $80

For maximizing profits,

Marginal cost =  Price of the commodity

4q = 80

q = 20 units

C = 200 + 2q^{2}

C = 200 + 2(20)^{2}

         = 200 + 800

         = 1,000

2. Profit = Total revenue - Total cost

             = (Price × Quantity) - TC

             = (80 × 20) - $1,000

             = $1,600 - $1,000

             = $600

3. We know that the firm in the short run will be produce at a point where total revenue is greater than the total variable cost

Average variable cost = variable cost ÷ quantity

                              =\frac{2Q^{2}}{Q}

                                     = 2Q

MC = 4Q

Here,  MC is greater than AVC at any given point.

so in the short run firm will producing short run positive profit.

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Answer:

He bought 40 shares.

Explanation:

<em>Step 1: Determine the initial stock price</em>

Use the expression below to determine the total initial stock price as shown;

T=S×s

where;

T=total initial stock price

S=initial stock price per share

s=number of shares

In our case;

T=$2,000

S=x

s=unknown

replacing;

2,000=x×s

s=2,000/x

<em>Step 2: Determine the final stock price</em>

Use the expression below;

F=f×s2

where;

F=final stock price=$2,000

f=final stock price per stock=(x-10)

s2=final number of shares bought=(2,000/x)+10

replacing;

2,000=(x-10){(2,000/x)+10)

2,000=x(2,000/x)+(10 x)-10(2,000/x)-100

(2,000=2,000+10 x-20,000/x-100)x

2,000 x=2,000 x+10 x²-20,000-100 x

2,000 x-2000 x=10 x²-100 x-20,000

10 x²-100 x-20,000=0

solving quadratically;

x=[100±√{100²-(4×10×-20,000)}]/(2×10)

x={100±√(10,000+800,000)}/20

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x=1,000/20=50

Initial stock price=$50

Number of shares bought=2,000/x=2,000/50=40

He bought 40 shares.

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