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lilavasa [31]
3 years ago
12

For there are 48 apples and 60 bananas and 96 oranges each basket must contain the same number of each type of frut Search inste

ad for there are 48 apppes and 60 banas and 96 onanges each basket must contain the same number of each type of frut
Mathematics
1 answer:
vaieri [72.5K]3 years ago
8 0

This question is incomplete

Complete Question

For there are 48 apples and 60 bananas and 96 oranges each basket must contain the same number of each type of fruit. Find the greatest number of baskets you can have

Answer:

The greatest number of baskets you can have is 12 baskets.

And each baskets would contain:

4 apples, 5 bananas and 8 oranges

Step-by-step explanation:

The factors of 48 are: 1, 2, 3, 4, 6, 8, 12, 16, 24, 48

The factors of 60 are: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60

The factors of 96 are: 1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48, 96

Then the greatest common factor is 12.

Therefore, the greatest number of baskets you can have is 12 baskets.

Each baskets would have

For apples

48 apples

48 apples / 12 baskets = 4 apples per basket

For bananas

60 bananas

60 bananas/12 baskets = 5 bananas per basket

For Oranges

96 Oranges/ 12 baskets = 8 oranges per baskets

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Answer:

(0, \frac{3}{10})

Step-by-step explanation:

To find the y-intercept of a graph, we can simply set the value of 'x' equal to 0. If we substitute this into the equation y= x²+3/10, we get:

y= 0²+3/10

y=3/10.

4 0
3 years ago
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Can someone PLEASE help me?
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Answer:

a

Step-by-step explanation:

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Please help, I can't figure out how to set this up. There's supposed to be 2 equations.
Valentin [98]

Hello from MrBillDoesMath

Answer:     + 4/7,   6 (13/14)

Discussion:

Let L be the larger of the two numbers and S the smaller of the two. Then the first sentence translates into this:


-6L - L = -4  =>

-7L = -4        =>          (divide both sides by -7)

L = - (-4)/(-7) = + 4/7       (*)


The second sentence translates to

2 (L + S) = 15  =>               (divide both sides by 2)

(L +S) = 15/2  =>                (subtract L from each side)

S = 15/2 - L = 15/2 - 4/7    (using (*) above)

So

S = 15*7/(2*7) - (4*2)/(7*2)       (combine over common denominator of 14)

S = 105/14 - 8/14 = 97/14 = 6 13/14

Something is crazy here!    While 2(L +S) = 15  -- check it out -- our larger number L ( =4/7) is actually smaller than the S number (6 13/14)!  Maybe I should have called them Y and X, respectively, as you suggested!

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jarptica [38.1K]
<h3>1.Area of the parallelogram= 288 square units</h3><h3>2.Area of the parallelogram=45 m^2</h3><h3>3.Area of the trapezoid   = 34 square in.</h3><h3>4.Area of the trapezoid = 8 square ft</h3><h3>5.Area of the rhombus= 27 square cm</h3><h3>6.Area of the rhombus= 108 square in</h3><h3>7.The area of the desktop is  = 1200 square in</h3><h3>8.The area of the rhombus is =84 cm^2</h3><h3>9.Area of the trapezoid  = 240 square ft</h3>

Step-by-step explanation:

1.

Base =16 ft and Height = 18 ft

Area of the parallelogram = base × height

                                       =16× 18 square units

                                       = 288 square units

2.

Base = 9 m and height = 5 m

Area of the parallelogram = base × height

                                        =(9×5) m^2

                                         =45 m^2

3 .

Height = 4 in and parallel sides are 12 in and 5 in

Area of the  trapezoid =\frac {1}{2} \times( {\textrm{sum of the parallel sides}}) \times height

                            =\frac{1}{2} \times (12+5) \times 4 square in.

                             = 34 square in.

4.

Height = 2 ft  and parallel sides are 2 ft and 6 ft

Area of the trapezoid =\frac {1}{2} \times( {\textrm{sum of the parallel sides}}) \times height

                              =\frac{1}{2} \times (2+6) \times 2 square ft

                              = 8 square ft

5.

Diagonals are 6 cm and 9 cm.

Area of the rhombus = \frac{1}{2}\times {\textrm{product of diagonals}

                               =\frac{1}{2 } \times 6\times 9 square cm

                               = 27 square cm

6. Diagonals are 12 in and 18 in

Area of the rhombus = \frac{1}{2}\times {\textrm{product of diagonals}

                               =\frac{1}{2 } \times 12\times 18 square in

                               = 108 square in

7. Given a desktop in the shape of a parallelogram has a base 30 in. and a height of 40 in

The area of the desktop is = (30 × 40 ) square in

                                            = 1200 square in

8. Given , a rhombus has one diagonal that is 14 cm and other diagonal 12 cm.

The area of the rhombus = \frac {1}{2} \times 14 \times 12 cm^2

                                         =84 cm^2

9.Given , the base of trapezoid are 24 ft  and 16 ft and height is 12 ft

Area of the trapezoid =\frac {1}{2} \times( {\textrm{sum of the parallel sides}}) \times height

                                    = \frac{1}{2} \times (24+16) \times 12 square ft

                                     = 240 square ft

8 0
3 years ago
What is the equivalent expressions 7+7+7
Fudgin [204]
7(3) is equivalent to 7 + 7 + 7

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hope this helps
5 0
3 years ago
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