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zysi [14]
3 years ago
13

Please answer this question

Mathematics
1 answer:
larisa86 [58]3 years ago
7 0

Answer: I think B

Step-by-step explanation:

Not fully sure

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Is 23.6404 greater than 23.64112?
melamori03 [73]

Answer:

No

Step-by-step explanation:

23.64112 > 23.6404

Reason : 1/1000 place value in 23.64112  is 1.

1/1000 place value in 23.6404  is 0.

4 0
3 years ago
Read 2 more answers
A rectangular garden is fenced on all sides with 278 feet of fencing. The garden is 9 feet longer than it is
JulijaS [17]
It’s 301 bc u add them together
6 0
3 years ago
Caden exercises daily by walking on a treadmill. He sets the machine so that he will walk at a steady rate of 3.6 miles per hour
babunello [35]

Answer:

a) d = 3.6t

b) 10.8 miles

c) 1.2 hours

Step-by-step explanation:

For part a:

Slope of a line: y = mx + b

In this case, the equation would be: d = mt,

where m represents the speed Caden is walking at.

Note: b = 0 in this case because when Caden starts walking on the treadmill, he hasn't really covered any distance yet.

Therefore, plugging in a speed of 3.6 miles per hour, the equation is:

d = 3.6t

For part b:

This is a simple instance of plugging in 3 hours for our t value.

Therefore, d = 3.6 (3)

d = 10.8 miles

For part c:

In this case, we are given that d = 4.32 miles.

Therefore, 4.32 = 3.6t

Dividing both sides by 3.6, we get

t = 1.2 hours

5 0
3 years ago
Solve If QR = 6x + 1, PR = 14x - 13, and PQ = 5x - 2, find PR
solong [7]

Answer:

P____Q____R

PR= PQ+ QR

(14x-13) = (5x-2)+(6x+1)

14x-13= 11x – 1

14x – 11x = 13–1

3x = 12

x= 12/ 3

x= 4

PR= 14x – 13 = 14 (4) – 13 = 18 – 13= 5

If you want (PQ , QR ) this is the solution

PQ =5x-2=5(4)-2=20-2=18

QR =6x+1=6(4)+1=24+1=25

I hope I helped you^_^

7 0
3 years ago
I need to know the answer to the question with the circle
KATRIN_1 [288]
___________________________

◆ AREA RELATED TO CIRCLES ◆ ___________________________

As shown in the figure ,

Radius of circle = 5 cm

Side of square = 2 × (Radius of inscribed circle)

Side of square = 2 × 5 cm

Side of square = 10 cm = a

___________________________

Now ,
Area of shaded region = (Area of square) - ( Area of inscribed circle )

Area of shaded region =
{a}^{2} - \pi {r}^{2}

Area of shaded region =
{10}^{2} - \frac{22}{7} \times {5}^{2}

Area of shaded region = 100 - 78.571

= 21.428 \: ans.

7 0
3 years ago
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