FACT: An organism's kingdom does not only describe physical characteristics.
Organisms are classified into the different kingdoms based on physical appearance, their function, how they reproduce and how they obtain their food.
EVIDENCE:
Kingdom Plantae: They obtain their food through photosynthesis
Reproduce asexually.
Kingdom Animalia : They obtain their food through hunting or consuming other organisms.
Reproduce sexually.
Answer:
A)What average intensity does a GPS receiver on the ground, directly below the satellite, receive? = 9.75 x 10 ∧-15w/m²
B)What is the amplitude of the electric field at the GPS receiver in part = 2.71 x 10 ∧-6nc
C)What is the amplitude of the magnetic field at the GPS receiver in part = 9.03 x 10∧-15T
D)How long does it take the signal to reach the receiver? = 6.73 x 10 ∧-2s
E)If the receiver is a square panel 2.00 on a side that absorbs all of the beam, what average pressure does the signal exert on it = 3.25 x10 ∧-25pa
F)What wavelength must the receiver be tuned to? = 0.190m
Explanation:
check attached files below for explanation
Answer:
0.088 seconds
0.0880000273785 second
0.08800054757 seconds
Explanation:
In the question it is given each century adds 1 ms to a day due to the slowing rotation of the Earth
In 88 centuries the length of the first day of the year will be
88 × 1 = 88 ms = 0.088 seconds
1 ms = 1 century
1 century = 100 years × 365.25 days
⇒1 ms = 36525 days

Sum of the gain on the first day would be
0.088 + 2.7378×10⁻⁸ = 0.0880000273785 second
Sum of the gain on the second day would be
0.088 + 2.7378×10⁻⁸+2.7378×10⁻⁸ = 0.08800054757 seconds
<span>Pitch and frequency are more or less the same thing - high pitch = high frequency.
The freqency of vibration of a string f = 1/length (L) so as length decreases the frequency increases.</span>
Answer:
The gauge pressure in Pascals inside a honey droplet is 416 Pa
Explanation:
Given;
diameter of the honey droplet, D = 0.1 cm
radius of the honey droplet, R = 0.05 cm = 0.0005 m
surface tension of honey, γ = 0.052 N/m
Apply Laplace's law for a spherical membrane with two surfaces
Gauge pressure = P₁ - P₀ = 2 (2γ / r)
Where;
P₀ is the atmospheric pressure
Gauge pressure = 4γ / r
Gauge pressure = 4 (0.052) / (0.0005)
Gauge pressure = 416 Pa
Therefore, the gauge pressure in Pascals inside a honey droplet is 416 Pa