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rosijanka [135]
3 years ago
10

How do you find the efficiency of a motorized machine given the work input and output?

Physics
1 answer:
musickatia [10]3 years ago
4 0
Output / input * 100 (Eg input-120 output-60 60/120=0.5 0.5*100=50 efficiency=50%)
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HELPPP!! Thanks!
vagabundo [1.1K]

Answer:

ok my brudda this makes no sense are you trying to fart or take a dump like what do you mean "increase the particle motion of a gas" sound like you need to take a massive dump or a massive fart so its bbc big black you know what saying

Explanation:

because its a bbc  .

5 0
3 years ago
A cat runs and jumps from one roof top to another which is 5 m away and 3 m below. Calculate the minimum horizontal speed with w
icang [17]
ThIs is the same type of problem
find out the time value
3 = 1/2*a*T^2
6/10 = t^2
t = 0.77 seconds
and the distance is given 5 m
thus speed ,= distance/time
speed = 5/0.77
= 6.45 m/s
6 0
3 years ago
When discussing what makes a material a good conductor you say they must
Readme [11.4K]

A material must readily accept electron flow to be a good conductor of electricity. Electrical conductors are electrical charge carriers with electrons that move with ease from atom to atom when charged with voltage. Examples of good conductors are copper, brass, steel, gold, and aluminum.

7 0
3 years ago
A vertical straight wire carrying an upward 28-A current exerts an attractive force per unit length of 7.83 X 10 N/m on a second
JulijaS [17]

Answer:

i_2 = 978750 A

Since the force between wires is attraction type of force so current must be flowing in upward direction

Explanation:

Force per unit length between two current carrying wires is given by the formula

F = \frac{\mu_0 i_1 i_2}{2 \pi d}

here we know that

F = 7.83 \times 10 N/m

d = 7.0 cm = 0.07 m

i_1 = 28 A

now we will have

F = \frac{4\pi \times 10^{-7} (28.0)(i_2)}{2\pi (0.07)}

7.83 \times 10 = \frac{2\times 10^{-7} (28 A)(i_2)}{0.07}

i_2 = 978750 A

Since the force between wires is attraction type of force so current must be flowing in upward direction

3 0
3 years ago
If the magnetic field in a traveling EM wave has a peak value of 17.9nT, what is the peak value of the electric field strength?
Doss [256]

Answer:

5.37 N/C

Explanation:

Peak value of magnetic field, Bo = 17.9 nT = 17.9 x 10^-9 T

The electromagnetic wave is produced when an oscillating electric and magnetic field interacts each other perpendicularly.

The direction of propagation of electromagnetic wave is perpendicular to both electric and magnetic field.

the relation between the electric field and magnetic field amplitudes is given by

c = \frac{E_{0}}{B_{0}}

where, c be the velocity of light, Eo be the peak value of electric field strength, Bo is the peak value of magnetic field strength.

3\times 10^{8} = \frac{E_{0}}{17.9\times 10^{-9}}}

Eo = 5.37 N/C

4 0
3 years ago
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