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3 years ago

The digestion process starts in the _____. esophagus stomach small intestine mouth

Chemistry

2 answers:

ahrayia [7]3 years ago

7 0

Your mouth is where the digestion process starts because when yo chew your food, nutrients is released into your body

tangare [24]3 years ago

7 0

Answer: mouth

Explanation:

The food digestion process in the human or animal body starts in the mouth. The mouth consists of teeth which helps in crushing and grinding of food. The mouth secretes saliva which provides lubrication to the food items. It helps in mixing process of the food so that it can be easily swallowed inside the gut and could enter into the digestive tract.

You might be interested in

How many grams of oxygen gas are there in a 2.3L tank at 7.5 atm and 24° C?

jolli1 [7]

Answer:

22.656 grams of oxygen gas are there in a 2.3L tank at 7.5 atm and 24° C

Explanation:

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law:

P * V = n * R * T

where R is the molar constant of the gases and n the number of moles.

In this case you know:

P= 7.5 atm
V= 2.3 L
n= ?

R= 0.082 $\frac{atm*L}{mol*K}$

T= 24 °C= 297 °K (being 0°C=273°K)

Replacing:

$7.5 atm* 2.3 L=n*0.082 \frac{atm*L}{mol*K} *297K$

Solving:

$n=\frac{7.5 atm* 2.3 L}{0.082 \frac{atm*L}{mol*K} *297K}$

n=0.708 moles

Knowing that oxygen gas is a diatomic gas of molecular form O₂ and its mass is 32 g / mole, you can apply the following rule of three: if 1 mole contains 32 grams, 0.708 moles, how much mass will it have?

$mass=\frac{0.708 moles*32 grams}{1mole}$

mass= 22.656 grams

22.656 grams of oxygen gas are there in a 2.3L tank at 7.5 atm and 24° C

8 0

4 years ago

Read 2 more answers

Olympic cyclist fill their tires with helium to make them lighter. Calculate the mass of air in an air filled tire and the mass

inn [45]

Answer: The mass difference between the two is 7.38 grams.

Explanation:

To calculate the number of moles, we use the equation given by ideal gas follows:

$PV=nRT$

where,

P = pressure = 125 psi = 8.50 atm (Conversion factor: 1 atm = 14.7 psi)

V = Volume = 855 mL = 0.855 L (Conversion factor: 1 L = 1000 mL)

T = Temperature = $25^oC=[25+273]K=298K$

R = Gas constant = $0.0821\text{ L. atm }mol^{-1}K^{-1}$

n = number of moles = ?

Putting values in above equation, we get:

$8.50atm\times 0.855L=n\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 298K\\\\n=\frac{8.50\times 0.855}{0.0821\times 298}=0.297mol$

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For air:

Moles of air = 0.297 moles

Average molar mass of air = 28.8 g/mol

Putting values in equation 1, we get:

$0.297mol=\frac{\text{Mass of air}}{28.8g/mol}\\\\\text{Mass of air}=(0.297mol\times 28.8g/mol)=8.56g$

Mass of air, $m_1$ = 8.56 g

For helium gas:

Moles of helium = 0.297 moles

Molar mass of helium = 4 g/mol

Putting values in equation 1, we get:

$0.297mol=\frac{\text{Mass of helium}}{4g/mol}\\\\\text{Mass of helium}=(0.297mol\times 4g/mol)=1.18g$

Mass of helium, $m_2$ = 1.18 g

Calculating the mass difference between the two:

$\Delta m=m_1-m_2$

$\Delta m=(8.56-1.18)g=7.38g$

Hence, the mass difference between the two is 7.38 grams.

5 0

3 years ago

Determinar los mililitros de solución 0.5 Normal de NaCl que se pueden preparar a partir de 3 L de solución de cloruro de sodio

MrMuchimi

Answer:

uhmmm english?

Explanation:

6 0

3 years ago

By what factor does the rate change in each of the following cases (assuming constant temperature)? (a) A reaction is first orde

Papessa [141]

Answer:

a) 2

b) 1/4

c) 9

Explanation:

a) for a first order reaction in reactant A

r initial = k*[A initial]

then if the concentration is doubled [A final ]= 2*[A initial] , then

r final = k*[A final ] = 2* k*[A initial] = 2*r initial

then the velocity changes by a factor of 2

b) for a second order reaction in reactant B

r initial = k*[B initial]²

then if the concentration is halved: [B final ]= [B initial]/2 , then

r final = k*[B final ]² = k*( [B initial]/2 )² =k* [B initial]² /4 = r initial /4

then the velocity changes by a factor of 1/4

c) for a second order reaction in reactant C

r initial = k*[C initial]²

then if the concentration is tripled : [C final ]= 3* [C initial] , then

r final = k*[C final ]² = k*( 3*[C initial] )² =k* [C initial]² *9 = 9 * r initial

then the velocity changes by a factor of 9

4 0

4 years ago

Q1.What is the mass of 5 moles Of 1.Mg 2.CaCO3 Q2. Calculate the number of atoms in 10g of Na Q3.calculate the number of molecul

Phoenix [80]

Answer:

Explanation:

Q1) as we know that moles=given mass/molar mass

mass of 5 moles of Mg is

mass =moles*molar mass

mass=5*24

mass=120 g

mass of 5 moles of CaCO3 is

mass= moles*molar mass

mass=5*100=500

Q2) number of atoms in 10 g Na

first we need number of moles of sodium

moles =mass/molar mass

moles=10/23=0.43

now we know that moles=number of atoms /avogadro number

for number of atom the formula become

number of atom=moles*avogadro number

number of atom=0.43*6.023*10^23=2.6*10^23

Q3)number of molecule in 10 g of NaCl

again we need number of moles of NaCl

moles=given mass/molar mass

moles=10/58.5=0.17

now number of molecules=moles*avogadro number

number of molecules=0.17*6.023*10^23=1.02*10^23

Q4) avogadro number is the number of particles(atoms,molecules,ions) present in one mole of a substance its value is 6.023*10^23

Q5)Number of atoms in 4g of oxygen

again we need number of moles of oxygen

moles=mass/molar mass

moles=4/16=0.25

now number of atoms=moles*avogadro number

number of atoms=0.25*6.023*10^23 =1.5*10^23

3 0

3 years ago