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<u>Answer:</u> The molarity of the stock solution is 4.64 M
<u>Explanation:</u>
To calculate the molarity of the diluted solution, we use the equation:
where,
are the molarity and volume of the stock solution
are the molarity and volume of diluted solution
We are given:
Putting values in above equation, we get:
Hence, the molarity of the stock solution is 4.64 M
Answer:
<em>The accurate label for the solution is</em><em> </em><u><em>2.00 mol/L NaCl.</em></u>
Explanation:
Molrity = mass ÷ molar mass
Molar mass of NaCL = 58.44 g/mol
Weighed mass = 116.9g
⇒ Molarity of the solution = = 2.0M
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<em>Therefore, the accurate label for the solution is </em><u><em>2.00 mol/L NaCl.</em></u>