<u>Answer:</u> The mass of solid NaOH required is 80 g
<u>Explanation:</u>
Equivalent weight is calculated by dividing the molecular weight by n factor. The equation used is:

where,
n = acidity for bases = 1 (For NaOH)
Molar mass of NaOH = 40 g/mol
Putting values in above equation, we get:

Normality is defined as the umber of gram equivalents dissolved per liter of the solution.
Mathematically,

Or,
......(1)
We are given:
Given mass of NaOH = ?
Equivalent mass of NaOH = 40 g/eq
Volume of solution = 400 mL
Normality of solution = 5 eq/L
Putting values in equation 1, we get:

Hence, the mass of solid NaOH required is 80 g
A compound is analyzed and found to contain 22.10%Al, 25.40%P, and 52.50%O
Let the total mass of compound = 100g
The mass of Aluminum = 22.10 g
Moles of Al = mass / atomic mass = 22.10 /23= 0.96
The mass of P = 25.40 g
Moles of P = 25.40 / 31 = 0.819
The mass of oxygen = 52.50 g
Moles of oxygen = 52.50 / 16= 3.28
The mole ratio of the two elements will be
Al = 0.96/0.819 = 1.17
P = 0.819/0.819 = 1
O = 3.28 / 0.819 = 4
The whole number ratio will be 1 : 1 : 4
So formula will be AlPO4
Answer:
The length of a side of the square is 4.53 cm
Explanation:
Volume (V) = mass/density
mass = 3.4 mg = 3.4/1000 = 0.0034 g
density = 19.3 g/cm^3
V = 0.0034/19.3 = 1.76×10^-4 cm^3
Volume = area × thickness
Area = volume/thickness = 1.76×10^-4/8.6×10^-6 = 20.48 cm^2
Length of one side of the square = sqrt(area of square) = sqrt(20.48 cm^2) = 4.53 cm