Answer:
You are looking for expected peaks in absorption spectra founded on structure of desired product, respectively on bound in desired compound. Every bond absorb specific energy from radiation which wavelength match to IR spectrum of light. Result of energy absorption is vibration of bond and bonded atoms (if they are not too heavy).That absorbed energy is seen as a peak in absorption spectra. These peaks are specific for each bound so you need to find peaks that mach to bounds in your desired compound and in that matter you can identify your compound.
In nuclear magnetic resonance you are looking for peaks specific for atoms in your desired compound (H or C atoms). When external magnetic field is applied, atom goes in higher energy state. When atoms goes "relaxing", it releasing energy that mach energy gap from relaxed end excited state. That energy is detected on nuclear magnetic resonance spectra and it depends on neighbor atom so you can determine the position of atoms and identify structure of desired compound.
For better results it is the best to combine these two methods.
Explanation:
Answer:
a, g, c
Explanation:
The conversion of the stable cyclopentane into Trans-1, 2dibromocyclopentane will require three step reactions.
The first is to convert the compound into a cyclopentene, through the addition of Bromine water under heat and photons (light). So option A is the first in the order. This will generate 1 bromocyclopentane through halogenation of the alkane. Secondly, a hot and strong base should be added like the NaOEt, EtOH to remove the added bromine and one atom of hydrogen from the resulting 1 bromocyclopentane in the previous reaction. This will yield cyclopentene, thus making the compound more electrophilic. So option g is required. Thirdly, bromine molecules will be added (C) to take up their places at the two electrophilic regions of the compound to produce Trans-1, 2dibromocyclopentane.
Answer:
Protons are positively charged. When a nucleus emits an alpha particle, these changes happen: the mass number decreases by 4. the atomic number decreases by 2.
Explanation:
