Answer:
The induced current in the loop is 1.2 A
Explanation:
Given;
length of the wire, L = 24 cm = 0.24 m
resistance of the wire, R = 0.14 Ω.
magnetic field strength, B = 0.55 T
time, t = 15 ms = 15 x 10⁻³ s
Circumference of a circle is given as;
L = 2πr
0.24 = 2πr
r = 0.24 / 2π
r = 0.0382 m
Area of a loop is given as;
A = πr²
A = π (0.0382)²
A = 0.004585 m²
Induced emf is given as;
Ф = ΔB x A
Ф = ( 0 - 0.55 T) x 0.004585 m²
Ф = -0.002522 T.m²
According to ohm's law;
V = IR
Where;
I is current
The induced current in the loop is calculated as;
I = V / R
I = 0.168 / 0.14
I = 1.2 A
Therefore, the induced current in the loop is 1.2 A
Answer:
80
Explanation:
because of the denstiy formula
de Broglie wavelength (λ) is given by the equation
λ = h/p
where h=Planck’s constant whose value is 6.62 x 10^(−34) joule-seconds and
p = momentum of the particle(here electron)
In terms of kinetic energy(E) momentum(p) can be written as,
p=(2mE)^1/2
where m=mass of the particle.
Hence λ becomes
1 λ = h(2mE)^-1/2
Given here, E = 13.6 eV = 13.6×1.6×10^-19 joule
m(mass of electron)= 9.1×10^-31 kg
Putting these values in equation (1) we get ,
λ =0.332×10^(-9) meter
=3.32×10^(-10) meter
=3.32 Å
Answer:
When i do exercise i feel great and happy afterwards ( there is a proven fact that after you go on a run, play a sport, or exercise you are proven to be more upbeat )
When i don't exercise i feel kinda lazy and tired mostly bored.
Alkali metal
Explanation:
In general, an alkali metal will be more reactive than an alkaline earth metal in the same period.
What determines reactivity of metals?
The electropositivity of metals determines how reactive they are.
- Electropositivity or metallicity is a measure of the tendency of atoms of an element to lose electrons.
- It is closely related to ionization energy and the electronegativity of an element.
- The lower the ionization energy of an element, the more electropositive or metallic it is
- Also, the more reactive it will be because, it can lose electrons more readily.
- Across a period from left to right, electropositivity decreases and from top to down a group, it increases.
- Since alkali metals are more electropositive than alkali earth metals, they are more reactive and readily lose their only electron.
- This is why the most reactive metal is francium found in the lower left corner on the periodic table.
- For non-metals, electronegativity is the most important factor.
Learn more:
Alkali metals brainly.com/question/6324347
Electronegativity brainly.com/question/11932624
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