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icang [17]
3 years ago
12

1. What is the kinetic energy of a ball with a mass of 5 kg rolling at 10 m/s?

Physics
1 answer:
Kazeer [188]3 years ago
5 0

KE=1/2mv^2

KE= 0.5×5kg×10m/s^2

KE=250J

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As one moves farther and farther from the Sun, the distance between adjacent planets is _____.
Alenkinab [10]
As one moves farther and farther from the Sun, the distance between adjacent planets is greater.
4 0
3 years ago
I need it now aaaasssssaaaappp!!!!
Vera_Pavlovna [14]

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5 0
3 years ago
What is the velocity if your going 105 miles every 10 minutes
Afina-wow [57]
The speed is 10.5 miles per minute, or 630 miles per hour.
We don't know the velocity, because you didn't tell us anything about the direction I'm going.
8 0
3 years ago
Read 2 more answers
A)
Savatey [412]

Answer:

Distance covered is equal to all the distance traveled.

So for example, if you go from A to B, and then from B to C, the total distance covered is AB + BC.

Displacement is equal to the difference between the final position and the initial position.

So if we go from A to B, the displacement is simply the line AB.

While if we go from A to B, and then from B to C, the displacement will be a segment that directly connects A and C, such that:

displacement = √( (AB)^2 + (BC)^2)

Now, if we want to find the points such that the magnitude of the distance covered is equal to the magnitude of the displacement, we need to look at the pairs that are directly connected by a straight line.

Those are:

A to B  ( or B to A)

B to C  (or C to B)

C to D  (or D to C)

7 0
3 years ago
a player passes a 0.600kg basketball down court for a fast break.the ball leaves the player hands with a speed of 8.30m/s and sl
Setler79 [48]

At the release point, the ball has kinetic energy,

\dfrac12m{v_0}^2

and at its maximum height it has potential and kinetic energy,

-mgy+\dfrac12mv^2

where y is the maximum height attained above the release point.

The LoCoE tells us that we should have

\dfrac12m{v_0}^2=-mgy+\dfrac12 mv^2

\implies v^2-{v_0}^2=-2gy

\implies\left(7.20\dfrac{\rm m}{\rm s}\right)^2-\left(8.30\dfrac{\rm m}{\rm s}\right)^2=-2\left(9.80\dfrac{\rm m}{\mathrm s^2}\right)y

\implies y=0.870\,\mathrm m

7 0
3 years ago
Read 2 more answers
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