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viktelen [127]
3 years ago
15

What would we need to know to calculate work and power

Physics
1 answer:
san4es73 [151]3 years ago
7 0

To calculate Work we need Force and Distance or Total Change in Energy and Heat.

To calculate Power we need Current and Voltage or Voltage and Resistance.

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The upward force acting on the wing of an airplane ir flight is called?​
Elza [17]

Answer:

Lift is the upward force on the wing acting perpendicular to the relative wind and perpendicular to the aircraft's lateral axis. Lift is required to counteract the aircraft's weight.

Explanation:

7 0
2 years ago
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What does the diameter in meters need to be of a round parachute that the designer has determined needs to have an area of 500 s
Marrrta [24]
Area of a circle is
A= pi r^2
so
500m^2 = 3.14 r2
500/pi = r ^2
152.1549...=r^2
square root both sides
r=12.61566...
d=2r
d=25.2
to 3 sig fig
4 0
3 years ago
Which best describes the difference between internal and thermal energy?
Dominik [7]
Internal energy cannot be transferred whereas, thermal energy is the energy due to temperature difference
7 0
3 years ago
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Will an object with a density of 1.05 g/ml float or sink in water? Explain.
WINSTONCH [101]
It will sink because it is heavier. The density of water 1.00 g/ml
7 0
3 years ago
A 10.00 kg mass is moving to the right with a velocity of 14.0 m/s. A 12.0 kg mass is moving to the left with a velocity of 8.00
Basile [38]

Answer:

2 m/s

Explanation:

From the conservation of momentum, the initial momentum of the system must be equal to the final momentum of the system.

Let the 10.00 kg mass be m_1 and the 12.0 kg mass be m_2. When they collide and stick, they have a combined mass of m_1+m_2.

Momentum is given by p=mv. Set up the following equation:

\displaystyle m_1v_1+m_2v_2=(m_1+m_2)v_f, where v_f is the desired final velocity of the masses.

Call the right direction positive. To indicate the 12.0 kg object is travelling left, its velocity should be substitute as -8.00 m/s.

Solving yields:

10\cdot 14 + 12\cdot (-8)=(10+12)v_f\\\implies v_f=\boxed{2 \text{ m/s}}

4 0
2 years ago
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