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viktelen [127]
3 years ago
15

What would we need to know to calculate work and power

Physics
1 answer:
san4es73 [151]3 years ago
7 0

To calculate Work we need Force and Distance or Total Change in Energy and Heat.

To calculate Power we need Current and Voltage or Voltage and Resistance.

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If a toy car has a centripetal acceleration of 50 m/s2 and was making the turn at 10 m/s. what was his radius
S_A_V [24]

Answer:

Explanation:

The centripetal acceleration is expressed as;

a = v²/r

a is the acceleration = 50m/s²

v is the velocity = 10m/s

r is the radius

To get the radius

r = v²/a

r = 10²/50

r = 100/50

r = 2m

Hence its radius is 2m

3 0
3 years ago
Two very large parallel sheets a distance d apart have their centers directly opposite each other. The sheets carry equal but op
andrew-mc [135]

Answer:

(A) F

Explanation:

See it in the pic.

8 0
3 years ago
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In an experiment if doubling the manipulated variable results in doubling of the responding variable the relationship between th
vodomira [7]
In an experiment if doubling the manipulated variable results in doubling of the responding variable the relationship between the variable is a direct. Having a direct relationship means that the<span> relationship between two numbers or other variables where an increase or decrease in one variable causes the same change to the other variable.</span>
6 0
3 years ago
rt A For a given substance, do you expect the density of the substance in its liquid state to be closer to the density in the ga
Nat2105 [25]

Answer:

A substance in its liquid state is closer to the density of its solid phase than the density of its gaseous phase.

Explanation:

For a substance in its liquid state we can expect the density of the substance more closer to the density of its solid state than its gaseous state because the the inter-molecular space is much close near to incompressible in the liquid state and the the inter-molecular force of attraction is much higher as compared to gaseous state.

In contrast to the molecular properties in liquid state gases have almost negligible inter-molecular force of attraction and very huge inter-molecular spacing which makes it well compressible.

8 0
3 years ago
A 1.5 kg orange falls from a tree and hits the ground in 0.75s. What is the speed of the orange just before it hits the ground?
Olenka [21]

The final speed of the orange is 7.35 m/s

Explanation:

The motion of the orange is a free fall motion, since there is only the force of gravity acting on it. Therefore, it is a uniformly accelerated motion with constant acceleration g=9.8 m/s^2 towards the ground. So we can use the following suvat equation:

v=u+at

where

v is the  final velocity

u is the initial velocity

a is the acceleration

t is the time elapsed

For the orange in this problem, we have

u = 0 (it is dropped from rest)

a=g=9.8 m/s^2 is the acceleration

Substituting t = 0.75 s, we find the final velocity (and speed) of the orange:

v=0+(9.8)(0.75)=7.35 m/s

Learn more about free fall:

brainly.com/question/1748290

brainly.com/question/11042118

brainly.com/question/2455974

brainly.com/question/2607086

#LearnwithBrainly

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