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Virty [35]
4 years ago
7

Two forces F1 and F2 are applied to a plank that supports a body of mass m, as shown in the figure. The distances between these

forces and the body of mass m are L1 and L2, respectively.
A. The values of F1 and F2 in static equilibrium depend on the choice of the axis of rotation.
B. In static equilibrium F1 = F2 for any values of L1 and L2.
C. The value of the sum (F1+ F2) that corresponds to static equilibrium is indepdendent of L1 and L2.
D. In static equilibrium, if L1 > L2, then F1 > F2.

Physics
1 answer:
Bad White [126]4 years ago
3 0

Answer:

The correct answer is - option C.

Explanation:

Given:

Two forces on a plank = F1 and F2

mass of plank = m

The distances between these forces and the body of mass m =  L1 and L2

we know that,

mg = F1 +F2 ( independent of L1 and L2)

so almost any point the value of the sum that corresponds to static equilibrium is independent of L1 and L2.

Thus, the correct answer is - option C.

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How do we find work from a force-displacement graph when the force exerted<br> is not constant?
Artemon [7]

Answer:

Explanation:

Read forces directly from the graph.

Read displacements directly from the graph.

Use the area under the graph to find the work done by the force. This is equal to the kinetic or potential energy the object gains due to the application of the force.

6 0
3 years ago
During a hard sneeze, your eyes might shut for 0.50 s. If you are driving a car at 90 km/h during such a sneeze, how far does th
Angelina_Jolie [31]

Answer:

12.5 m.

Explanation:

Speed: This can be defined as the rate of change of distance. The S.I unit of speed is m/s. Mathematically it can be expressed as,

Speed = distance/time

S = d/t......................... Equation 1

d = S×t ...................... Equation 2.

Where S = speed of the car, d = distance, t = time taken to shut the eye during sneezing

Given: S = 90 km/h, t = 0.50 s.

Conversion: 90 km/h ⇒ m/s = 90(1000/3600) = 25 m/s.

S = 25 m/s.

Substitute into equation 2.

d = 25×0.50

d = 12.5 m.

Hence the car will move 12.5 m during that time

5 0
3 years ago
Which structure is represented by the letter D? Choose 1 answer: (Choice A) A Chloroplast (Choice B) B Vacuole (Choice C) C Mito
Otrada [13]

Answer:

vacuole

Explanation:

Remember vacuoles in plant cells are a lot bigger than there animal cell counterparts.

6 0
3 years ago
Brainliest if correct
ozzi

Answer:

It's is c coz the weight is equal to the normal force

7 0
3 years ago
The driver of a 1750 kg car traveling on a horizontal road at 110 km/h suddenly applies the brakes. Due to a slippery pavement,
Alexeev081 [22]

Answer: a=-2.4525 m/s^2

d=s=190.3 m

Explanation:The only force that is stopping the car and causing deceleration is the frictional force Fr

Fr = 25% of weight

W=mg

W=1750*9.81

W=17167.5

Hence

Fr=\frac{25}{100} * -17167.5\\\\Fr=-4291.875 N

Frictional force is negative as it acts in opposite direction

According to newton second law of motion

F=ma

hence

a=Fr/m

a=-4291.875/1750\\a=-2.4525

given

u= 110 km/h

u=110*1000/3600

u=30.55 m/s

to get t we know that final velocity v=0

v^2=u^2+2as\\0=30.55^2-2*2.4525*s\\s=190.34m

3 0
3 years ago
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