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garri49 [273]
4 years ago
9

Consider a reversible heat engine that employs a hot reservoir at a temperature of 610 K and a cold reservoir at 290 K. (a) What

is the entropy change of the hot reservoir during a period in which 4730 J is extracted from the hot reservoir? 7.75 J/K
Physics
1 answer:
Pavlova-9 [17]4 years ago
6 0

To solve this problem it is necessary that we start from the definition of entropy as a function of heat and temperature exchange. Mathematically this thermodynamic expression can be described as

\Delta S = \frac{Q}{T}

Where,

Q= Heat exchange

T = Temperature

Since we look for entropy in the hot reservoir, and considering our given values we have to

T_H = 610K\\T_C = 290K \\Q_H = 4730J

Replacing we have:

\Delta S_H= \frac{Q_H}{T_H}

\Delta S_H = \frac{4730J}{610K}

\Delta S_H = 7.754J/K

Therefore the final change in the entropy is 7.75J/K

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Each time you move down a step you move the decimal to the right, each time you move up a step you move the decimal to the left.

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Which force diagram accurately represents a satellite in orbit around Earth?
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First choice

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<h3>What is the  Brundtland Commission?</h3>

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